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Consider allowing abs_sub #89

@ada4a

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@ada4a

In L11L03 (and I'm pretty sure in some previous level(s) as well), we essentially derive abs_sub:

have f2 : |a m| = |(a m - a N) + a N| := by ring_nf
have f3 : |(a m - a N) + a N| ≤ |a m - a N| + |a N| := by apply abs_add

It would be nice to have access to that theorem -- one could imagine its derivation being a (rather simple) problemset exercise

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