Given two integer arrays nums1
and nums2
, return an array of their intersection. Each element in the result must be unique and you may return the result in any order.
Example 1:
Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2]
Example 2:
Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Explanation: [4,9] is also accepted.
Constraints:
1 <= nums1.length, nums2.length <= 1000
0 <= nums1[i], nums2[i] <= 1000
class Solution:
def intersection(self, nums1: List[int], nums2: List[int]) -> List[int]:
s1, s2 = set(nums1), set(nums2)
return list(s1 & s2)
class Solution {
public int[] intersection(int[] nums1, int[] nums2) {
Set<Integer> s1 = transfer(nums1);
Set<Integer> s2 = transfer(nums2);
s1.retainAll(s2);
int[] output = new int[s1.size()];
int i = 0;
for (Integer e : s1) {
output[i++] = e;
}
return output;
}
private Set<Integer> transfer(int[] nums) {
Set<Integer> s = new HashSet<>();
for (int e : nums) {
s.add(e);
}
return s;
}
}