There are n
houses in a village. We want to supply water for all the houses by building wells and laying pipes.
For each house i
, we can either build a well inside it directly with cost wells[i - 1]
(note the -1
due to 0-indexing), or pipe in water from another well to it. The costs to lay pipes between houses are given by the array pipes
, where each pipes[j] = [house1j, house2j, costj]
represents the cost to connect house1j
and house2j
together using a pipe. Connections are bidirectional.
Return the minimum total cost to supply water to all houses.
Example 1:
Input: n = 3, wells = [1,2,2], pipes = [[1,2,1],[2,3,1]] Output: 3 Explanation: The image shows the costs of connecting houses using pipes. The best strategy is to build a well in the first house with cost 1 and connect the other houses to it with cost 2 so the total cost is 3.
Constraints:
1 <= n <= 104
wells.length == n
0 <= wells[i] <= 105
1 <= pipes.length <= 104
pipes[j].length == 3
1 <= house1j, house2j <= n
0 <= costj <= 105
house1j != house2j