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中文文档

Description

Table: Customer

+---------------+---------+

| Column Name   | Type    |

+---------------+---------+

| customer_id   | int     |

| name          | varchar |

| visited_on    | date    |

| amount        | int     |

+---------------+---------+

(customer_id, visited_on) is the primary key for this table.

This table contains data about customer transactions in a restaurant.

visited_on is the date on which the customer with ID (customer_id) have visited the restaurant.

amount is the total paid by a customer.

 

You are the restaurant owner and you want to analyze a possible expansion (there will be at least one customer every day).

Write an SQL query to compute moving average of how much customer paid in a 7 days window (current day + 6 days before) .

The query result format is in the following example:

Return result table ordered by visited_on.

average_amount should be rounded to 2 decimal places, all dates are in the format ('YYYY-MM-DD').

 

Customer table:

+-------------+--------------+--------------+-------------+

| customer_id | name         | visited_on   | amount      |

+-------------+--------------+--------------+-------------+

| 1           | Jhon         | 2019-01-01   | 100         |

| 2           | Daniel       | 2019-01-02   | 110         |

| 3           | Jade         | 2019-01-03   | 120         |

| 4           | Khaled       | 2019-01-04   | 130         |

| 5           | Winston      | 2019-01-05   | 110         | 

| 6           | Elvis        | 2019-01-06   | 140         | 

| 7           | Anna         | 2019-01-07   | 150         |

| 8           | Maria        | 2019-01-08   | 80          |

| 9           | Jaze         | 2019-01-09   | 110         | 

| 1           | Jhon         | 2019-01-10   | 130         | 

| 3           | Jade         | 2019-01-10   | 150         | 

+-------------+--------------+--------------+-------------+



Result table:

+--------------+--------------+----------------+

| visited_on   | amount       | average_amount |

+--------------+--------------+----------------+

| 2019-01-07   | 860          | 122.86         |

| 2019-01-08   | 840          | 120            |

| 2019-01-09   | 840          | 120            |

| 2019-01-10   | 1000         | 142.86         |

+--------------+--------------+----------------+



1st moving average from 2019-01-01 to 2019-01-07 has an average_amount of (100 + 110 + 120 + 130 + 110 + 140 + 150)/7 = 122.86

2nd moving average from 2019-01-02 to 2019-01-08 has an average_amount of (110 + 120 + 130 + 110 + 140 + 150 + 80)/7 = 120

3rd moving average from 2019-01-03 to 2019-01-09 has an average_amount of (120 + 130 + 110 + 140 + 150 + 80 + 110)/7 = 120

4th moving average from 2019-01-04 to 2019-01-10 has an average_amount of (130 + 110 + 140 + 150 + 80 + 110 + 130 + 150)/7 = 142.86

Solutions

SQL