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if (scale == 0 && subscale == 0) { item->valuedouble = item->sign * d; item->valueint = item->sign * n; item->type = cJSON_Int; } else { printf("subscale = %d, signsubscale = %d, s = %.16f\n", subscale, signsubscale, d); if (subscale != 0) { d = item->sign * base * pow(10.0, (scale + subscale * signsubscale)); /* number = +/- number.fraction * 10^+/- exponent */ } item->valuedouble = d; item->valueint = n; printf("d = %.16f, base = %.16f, valuedouble = %.16f\n", d, base, item->valuedouble); item->type = cJSON_Double; }
经测试,负double值时,scale < 0, subscale == 0, item->sign < 0,d值并不会经过d * item->sign,因此解析出来的只会是正值。
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调用哪个函数获取值的时候负double会取到正值? 如果是 operator() 这个方法,两个月前已修复,更新一下最新代码即可。
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经测试,负double值时,scale < 0, subscale == 0, item->sign < 0,d值并不会经过d * item->sign,因此解析出来的只会是正值。
The text was updated successfully, but these errors were encountered: