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APIレスポンスの""(から文字)をハンドリングする。 #33

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yamanetaisei opened this issue Feb 27, 2021 · 0 comments
Open

APIレスポンスの""(から文字)をハンドリングする。 #33

yamanetaisei opened this issue Feb 27, 2021 · 0 comments
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起こっている問題

recommended_urlがnilでなく、""で返ってくるので、recommended_urlオプショナルで定義をしてしまっているために、無駄なnullチェックが入ってる

対応方針

  • recommend_urlのオプショナルではなく、普通の変数で定義
  • 値の有無はisEmptyで判定
@yamanetaisei yamanetaisei added the bug Something isn't working label Feb 27, 2021
@yamanetaisei yamanetaisei self-assigned this Feb 27, 2021
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