From 7dfe90c551d8e6377d645bafefcdefab871ea606 Mon Sep 17 00:00:00 2001
From: anjanisinghal21 <91344343+anjanisinghal21@users.noreply.github.com>
Date: Fri, 29 Oct 2021 20:10:02 +0530
Subject: [PATCH 1/2] bubble_sort.c

---
 BubbleSort.c | 44 ++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 44 insertions(+)
 create mode 100644 BubbleSort.c

diff --git a/BubbleSort.c b/BubbleSort.c
new file mode 100644
index 0000000..45d5435
--- /dev/null
+++ b/BubbleSort.c
@@ -0,0 +1,44 @@
+// C++ program for implementation of Bubble sort
+#include <bits/stdc++.h>
+using namespace std;
+
+void swap(int *xp, int *yp)
+{
+	int temp = *xp;
+	*xp = *yp;
+	*yp = temp;
+}
+
+// A function to implement bubble sort
+void bubbleSort(int arr[], int n)
+{
+	int i, j;
+	for (i = 0; i < n-1; i++)	
+	
+	// Last i elements are already in place
+	for (j = 0; j < n-i-1; j++)
+		if (arr[j] > arr[j+1])
+			swap(&arr[j], &arr[j+1]);
+}
+
+/* Function to print an array */
+void printArray(int arr[], int size)
+{
+	int i;
+	for (i = 0; i < size; i++)
+		cout << arr[i] << " ";
+	cout << endl;
+}
+
+// Driver code
+int main()
+{
+	int arr[] = {64, 34, 25, 12, 22, 11, 90};
+	int n = sizeof(arr)/sizeof(arr[0]);
+	bubbleSort(arr, n);
+	cout<<"Sorted array: \n";
+	printArray(arr, n);
+	return 0;
+}
+
+// This code is contributed by rathbhupendra

From 67fd59569f205494da7aad2e4d0da5ca417bbe08 Mon Sep 17 00:00:00 2001
From: anjanisinghal21 <91344343+anjanisinghal21@users.noreply.github.com>
Date: Fri, 29 Oct 2021 20:13:30 +0530
Subject: [PATCH 2/2] Lucky no in C is created.

---
 Lucky_numbers.c | 38 ++++++++++++++++++++++++++++++++++++++
 1 file changed, 38 insertions(+)
 create mode 100644 Lucky_numbers.c

diff --git a/Lucky_numbers.c b/Lucky_numbers.c
new file mode 100644
index 0000000..24b7601
--- /dev/null
+++ b/Lucky_numbers.c
@@ -0,0 +1,38 @@
+// C++ program for Lucky Numbers
+#include <bits/stdc++.h>
+using namespace std;
+#define bool int
+
+/* Returns 1 if n is a lucky no.
+otherwise returns 0*/
+bool isLucky(int n)
+{
+	static int counter = 2;
+	
+	if(counter > n)
+		return 1;
+	if(n % counter == 0)
+		return 0;
+	
+	/*calculate next position of input no.
+	Variable "next_position" is just for
+	readability of the program we can
+	remove it and update in "n" only */
+	int next_position = n - (n/counter);
+	
+	counter++;
+	return isLucky(next_position);
+}
+
+// Driver Code
+int main()
+{
+	int x = 5;
+	if( isLucky(x) )
+		cout << x << " is a lucky no.";
+	else
+		cout << x << " is not a lucky no.";
+}
+
+// This code is contributed
+// by rathbhupendra