[Donghae0230] WEEK 03 solutions #2118
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seungriyou
approved these changes
Nov 30, 2025
| def devide_by_2 (self, n, temp): | ||
| if n > 1 : | ||
| temp.append(n % 2) | ||
| return self.devide_by_2(n // 2, temp) |
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n & n-1로 오른쪽에서부터 1인 비트를 하나씩 지워가며 개수를 세는 방식인 Brian Kernighan's 알고리즘이라는 방법도 있어 공유드립니다~!
| return | ||
| for i in range(start, len(candidates)): | ||
| combination.append(candidates[i]) | ||
| backtrack(i, combination) |
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가독성 좋은 백트래킹 풀이인 것 같습니다!
여기에 추가로 candidates를 정렬한다면 pruning을 적용할 수 있어 더 최적화 된 풀이가 가능할 것 같아요~!
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