issue with saphyra.py

[ReddyKousic]

how to resolve it

[swordapi]

Use python2 saphyra.py http://target.com/

[XFORWORKS]

Hey @ReddyKousic,

Here's the code for an HTTP/S Protocol.
Paste this at the end of the script :

                url = sys.argv[1]
		if url.count("/")==2:
			url = url + "/"
		m = re.search("http\://([^/]*)/?.*", url)
                m2 = re.search("https\://([^/]*)/?.*", url)
                try:
		    host = m.group(1)
                except:
                    host = m2.group(1)
		for i in range(700):
			t = HTTPThread()
			t.start()
		t = MonitorThread()
		t.start()

I hope we helped you, the script just needed some pretty simple editing.

• XForWorks

[iqbalwalker]

nice just missed it

[swordapi]

@XFORWORKS I get a error

~/Anonymous $ python2 saphyra.py https://dstat.cc/
File "saphyra.py", line 3535
if url.count("/")==2:
^
IndentationError: unexpected indent

[swordapi]

@XFORWORKS
Can you upload the by you exited script to mega or anonfiles?

[XFORWORKS]

@sinaj2889
I could do that but the script is remade so it's not working like it was before. The error you have on that line is because of space input, see if you pasted it correctly. If there is a problem, tell me.

• XForWorks ( Retr0 )

[swordapi]

@XFORWORKS thanks for your fast reply the problem is if I just paste it will be all on one line and I dont think that will work and I tried doing the spaces but it didn't work

[swordapi]

@XFORWORKS can you add spaces or what do you mean by remade I can just replace it then by your version

[XFORWORKS]

@sinaj2889
Here is an example of the space input. :

• XForWorks ( Retr0 )

[swordapi]

@XFORWORKS What about pasting the whole script to paste.it

[swordapi]

@XFORWORKS okkk I'm working with my team against Russia so how can we contact you and what do you mean with false persons

[swordapi]

@XFORWORKS this name is not valid on Discord

[mixc2]

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