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Solution_17.cpp
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//
// Created by houmo on 19-2-25.
//
/*
* Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent.
A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters.
Example:
Input: "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.
*/
#include "Solution_17.h"
vector<string> Solution_17::letterCombinations(string digits) {
vector<vector<char >> ss;
vector<char> s2 = {'a','b','c'};
vector<char> s3 = {'d','e','f'};
vector<char> s4 = {'g','h','i'};
vector<char> s5 = {'j','k','l'};
vector<char> s6 = {'m','n','o'};
vector<char> s7 = {'p','q','r','s'};
vector<char> s8 = {'t','u','v'};
vector<char> s9 = {'w','x','y','z'};
ss.push_back(s2);
ss.push_back(s3);
ss.push_back(s4);
ss.push_back(s5);
ss.push_back(s6);
ss.push_back(s7);
ss.push_back(s8);
ss.push_back(s9);
vector<int> carryBit;
vector<int> valuesIndex;
int sizeOfDigits = 1;
for(int i=0; i<digits.size();i++){
sizeOfDigits *= ss[digits[i]-50].size();
carryBit.push_back(0);
valuesIndex.push_back(0);
}
if(digits.size()==0){
sizeOfDigits = 0;
}
vector<string> answer;
for(int i=0; i<sizeOfDigits; i++){
string Temp = string(digits.size(),'0');
valuesIndex[digits.size()-1] = i%ss[digits[digits.size()-1]-50].size();
Temp[digits.size()-1] = ss[digits[digits.size()-1]-50][valuesIndex[digits.size()-1]];
if(i%ss[digits[digits.size()-1]-50].size()==0 && i!=0){
carryBit[digits.size()-2] = 1;
}
for(int j=digits.size()-2; j>=0;j--){
if(carryBit[j] == 1){
if(valuesIndex[j]+1>=ss[digits[j]-50].size()){
valuesIndex[j] = 0;
if(j!=0){
carryBit[j-1] = 1;
}
} else{
valuesIndex[j] += 1;
}
carryBit[j] = 0;
}
Temp[j] = ss[digits[j]-50][valuesIndex[j]];
}
answer.push_back(Temp);
}
return answer;
}