new solution envs for mock up exam

Author: wallscheid

exam/examClass.cls

@@ -119,30 +119,29 @@
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 %% Solution table %%
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
-\NewDocumentEnvironment{solutiontable}{+b}{
-    \table[ht]
-    \captionsetup{labelfont={color=blue},textfont={color=blue}}
-    \color{blue}
-    #1}
-    {
-        \endtabularx
-        \endtable
-    }
+\DeclareFloatingEnvironment[autorefname=Sol.-Tab.]{solutiontable}
+\captionsetup[solutiontable]{name=Solution Table, labelfont={color=blue},textfont={color=blue}}
+\renewcommand{\thesolutiontable}{\arabic{solutiontable}}
+
+% Change autorefname of table to Tab.
+\addto\extrasenglish{%
+    \renewcommand{\tableautorefname}{Tab.}%
+}
+    
 
 
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 %% Solution figure %%
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
-\NewDocumentEnvironment{solutionfigure}{+b}{
-    \figure
-    \captionsetup{labelfont={color=blue},textfont={color=blue}}
-    \color{blue}
-    #1}
-    {
-        \endfigure
-    }
+\DeclareFloatingEnvironment[autorefname=Sol.-Fig.]{solutionfigure}
+\captionsetup[solutionfigure]{name=Solution Figure, labelfont={color=blue},textfont={color=blue}}
+\renewcommand{\thesolutionfigure}{\arabic{solutionfigure}}
 
-\renewcommand{\figurename}{Fig.}
+
+% Change autorefname of figure to Fig.
+\addto\extrasenglish{%
+    \renewcommand{\figureautorefname}{Fig.}%
+}
 
 
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
@@ -164,6 +163,8 @@
     \fi
     \normalsize
     \setlength{\parskip}{1em}
+    \setcounter{solutionfigure}{0}
+    \setcounter{solutiontable}{0}
 }
 
 \titleformat*{\section}{\normalfont}

exam/summer2024/tex/task01.tex

@@ -15,8 +15,8 @@
 
 
 
-\subtask{The disc from Fig.~\ref{fig:faraday_disk} has a diameter of $d=\SI{60}{\cm}$ and is rotating with the circumferential speed $v_\mathrm{d} = \SI{100}{\meter\per\second}$. What is the rotational speed and angular velocity of the copper disk?}{2}
-\subtaskGerman{Die Scheibe aus Abb.~\ref{fig:faraday_disk} hat einen Durchmesser von $d=\SI{60}{\cm}$ und ihre Oberfläche rotiert mit der Umfangsgeschwindigkeit $v_\mathrm{d} = \SI{100}{\meter\per\second}$. Wie groß ist die Drehzahl $n_\mathrm{d}$ und die Winkelgeschwindigkeit $\omega_\mathrm{d}$ der Kupferscheibe?}
+\subtask{The disc from \autoref{fig:faraday_disk} has a diameter of $d=\SI{60}{\cm}$ and is rotating with the circumferential speed $v_\mathrm{d} = \SI{100}{\meter\per\second}$. What is the rotational speed and angular velocity of the copper disk?}{2}
+\subtaskGerman{Die Scheibe aus \autoref{fig:faraday_disk} hat einen Durchmesser von $d=\SI{60}{\cm}$ und ihre Oberfläche rotiert mit der Umfangsgeschwindigkeit $v_\mathrm{d} = \SI{100}{\meter\per\second}$. Wie groß ist die Drehzahl $n_\mathrm{d}$ und die Winkelgeschwindigkeit $\omega_\mathrm{d}$ der Kupferscheibe?}
 
 \begin{solutionblock}
     The rotational speed is given by

exam/summer2024/tex/task02.tex

@@ -34,8 +34,8 @@
 \end{center}
 \end{solutionblock}
 
-\subtask{Now consider a DC machine with the parameters given in Tab.~\ref{tab:characteristicsDC_task2}. To which of the above connection type can the parameter set belong?}{1}
-\subtaskGerman{Betrachten Sie nun eine Gleichstrommaschine mit den Parametern aus Tab.~\ref{tab:characteristicsDC_task2}. Zu welchen der obigen Verschaltungsarten kann dieser Parametersatz gehören?}
+\subtask{Now consider a DC machine with the parameters given in \autoref{tab:characteristicsDC_task2}. To which of the above connection type can the parameter set belong?}{1}
+\subtaskGerman{Betrachten Sie nun eine Gleichstrommaschine mit den Parametern aus \autoref{tab:characteristicsDC_task2}. Zu welchen der obigen Verschaltungsarten kann dieser Parametersatz gehören?}
 \begin{table}[htb]
     \caption{Characteristics of the given DC machine.}
     \centering

exam/summer2024/tex/task03.tex

@@ -18,8 +18,8 @@
     If $\omega_\mathrm{r}=\SI{0}{\per\second}$ the mechanical rotor frequency is zero and the slip angular frequency is equal to the electrical angular frequency of the stator excitation: $\omega_\mathrm{s}= \omega_\mathrm{slip}$. Consequently, the slip ratio is equal to one ($s=\omega_\mathrm{slip}/\omega_\mathrm{s}=1$) and could be dropped from the equivalent circuit diagram.
 \end{solutionblock}
 
-\subtask{From now on consider a \textbf{squire cage induction machine} with the  parameters from Tab.~\ref{tab:characteristicsIM_task3}. Calculate the no-load speed $n_0$. }{2}
-\subtaskGerman{Wir betrachten nun eine \textbf{Käfigläufer-Asynchronmaschine} mit den Parametern aus Tab.~\ref{tab:characteristicsIM_task3}. Berechnen Sie die Leerlaufdrehzahl $n_0$.}
+\subtask{From now on consider a \textbf{squire cage induction machine} with the  parameters from \autoref{tab:characteristicsIM_task3}. Calculate the no-load speed $n_0$. }{2}
+\subtaskGerman{Wir betrachten nun eine \textbf{Käfigläufer-Asynchronmaschine} mit den Parametern aus \autoref{tab:characteristicsIM_task3}. Berechnen Sie die Leerlaufdrehzahl $n_0$.}
 \begin{table}[htb]
     \caption{Characteristics of the given induction machine.}
     \centering

exam/summer2024/tex/task04.tex

@@ -25,8 +25,8 @@
 \end{figure}
 
 
-\subtask{Determine the operating mode of the machine characterized by Fig.~\ref{fig:phasor_SM}.}{2}
-\subtaskGerman{Bestimmen Sie die Betriebsart der Maschine auf Basis von Abb.~\ref{fig:phasor_SM}.}
+\subtask{Determine the operating mode of the machine characterized by \autoref{fig:phasor_SM}.}{2}
+\subtaskGerman{Bestimmen Sie die Betriebsart der Maschine auf Basis von \autoref{fig:phasor_SM}.}
 
 \begin{solutionblock}
     The machine is operating as an overexcited generator, since the excitation voltage $\underline{U}_\mathrm{i}$ is leading the stator voltage $\underline{U}_\mathrm{s}$ by an angle $\theta$ and the induced voltage amplitude is larger than the stator voltage amplitude.
@@ -39,7 +39,7 @@
 \begin{solutionblock}
     The short-circuit current $\underline{I}_\mathrm{s,sc}$ is orthogonal to $\underline{U}_\mathrm{i}$ and lagging behind by $\SI{90}{\degree}$, that is, pointing towards the real axis with a length of \SI{1.33}{\cm}. The synchronous reactance is then
     $$X_\mathrm{s} = \frac{\underline{U}_\mathrm{i}}{\underline{I}_\mathrm{s,sc}} = \frac{\SI{3}{\kilo\volt}}{\SI{1.33}{\kilo\ampere}} = \SI{2.26}{\ohm}.$$
-    Here, the induced voltage $\underline{U}_\mathrm{i}$ has been obtained from optical measurement of the phasor diagram and also represents the open-circuit voltage.
+    Here, the induced voltage $\underline{U}_\mathrm{i}$ has been obtained from optical measurement of the phasor diagram and also represents the open-circuit voltage. The completed phasor diagram is shown in \autoref{fig:phasor_SM_final}.
 \end{solutionblock}
 
 
@@ -54,11 +54,8 @@
     The angle $\varphi$ is then
     $$\varphi = -\arccos(0.96) = \SI{-16.25}{\degree}.$$
     The power factor angle is negative as the generator operates in an over-excited mode, i.e., its reactive power is negative. The resulting complex stator current is then $$\underline{I}_\mathrm{s} = \SI{0.62}{\kilo\ampere} \cdot e^{\mathrm{j}(\SI{16.25}{\degree} + \SI{63.5}{\degree})}  = \SI{0.11}{\kilo\ampere} + \mathrm{j} \SI{0.61}{\kilo\ampere}.$$
-    Here, the angle $\SI{63.5}{\degree}$ is the stator voltage angle counted from the real axis.
-\end{solutionblock}
-
-\begin{solutionblock}
-    \begin{figure}[h!]
+    Here, the angle $\SI{63.5}{\degree}$ is the stator voltage angle counted from the real axis. The final solution phasor diagram is shown in \autoref{fig:phasor_SM_final}.
+    \begin{solutionfigure}[ht]
         \centering
         \begin{tikzpicture}
             \coordinate (b) at (0,0);
@@ -77,8 +74,12 @@
             \pic[draw, <-, angle eccentricity=1.7, angle radius=1.25cm]{angle = a--b--d};
             \node at (0.45,1.5) {$\varphi$};
         \end{tikzpicture}
-    \end{figure}
+        \caption{Final phasor diagram}
+        \label{fig:phasor_SM_final}
+    \end{solutionfigure}
 \end{solutionblock}
+  
+
 
 \subtask{Determine the apparent power $S$ and the reactive power $Q$.}{2}
 \subtaskGerman{Bestimmen Sie die Scheinleistung $S$ und die Blindleistung $Q$.}