diff --git a/exercise/tex/exercise01.tex b/exercise/tex/exercise01.tex
index a52f74b..75577c5 100644
--- a/exercise/tex/exercise01.tex
+++ b/exercise/tex/exercise01.tex
@@ -349,12 +349,12 @@
     
     As the conductor is flexibly connected to the battery via flexible connections the force $F$ in the air gap accelerates it to the right in its direction.
 
-    \begin{figure}[ht]
+    \begin{solutionfigure}[ht]
         \centering
         \includegraphics{ex01/solution_LorentzForce.pdf}
         \caption{Acting Lorentz force on the conductor in the air gap.}
         \label{fig:solution_LorentzForce}
-    \end{figure}
+    \end{solutionfigure}
 
 \end{solutionblock}
 
@@ -386,12 +386,12 @@
 
     As long as $v B_{\updelta} l$ is less than $U_{\mathrm{B0}}$, is $I$ > 0 and the driving force $F$ > 0 remains effective. The induced voltage acts against the current direction $I$, which is the cause of the conductor movement through $F$, and therefore acts against the cause of its creation (Lenz's rule, Fig.~\ref{fig:solution_movingConductor}).
 
-    \begin{figure}[ht]
+    \begin{solutionfigure}[ht]
         \centering
         \includegraphics{ex01/solution_movingConductor.pdf}
         \caption{Moving conductor with the induced voltage $u_{\mathrm{i}}$ as an external voltage, a) equivalent electrical circuit diagram, b) direction of the Lorentz force $F$.}
         \label{fig:solution_movingConductor}
-    \end{figure}
+    \end{solutionfigure}
 
 \end{solutionblock}
 
@@ -457,12 +457,12 @@
     \end{equation}
 
     The Lorentz force and the friction force are visualized in Fig.~\ref{fig:solution_LorentzForce_balanceOfForces} after reaching the final speed.
-    \begin{figure}[ht]
+    \begin{solutionfigure}[ht]
         \centering
         \includegraphics{ex01/solution_LorentzForce_balanceOfForces.pdf}
         \caption{Indicates the balance of forces after reaching the final speed.}
         \label{fig:solution_LorentzForce_balanceOfForces}
-    \end{figure}
+    \end{solutionfigure}
 
 \end{solutionblock}
 
@@ -490,12 +490,12 @@
         F = I l B_{\updelta},
     \end{equation}
     and the resulting values are shown in der right part of Fig.~\ref{fig:solution_conductorSpeed}.
-    \begin{figure}[ht]
+    \begin{solutionfigure}[ht]
         \centering
         \includegraphics{ex01/solution_conductorSpeed.pdf}
         \caption{Current and force of the conductor in relationship to the velocity.}
         \label{fig:solution_conductorSpeed}
-    \end{figure}
+    \end{solutionfigure}
 
 \end{solutionblock}