Difficulty: hard
Link: https://leetcode.com/problems/minimum-cost-to-equalize-array/
Contains PNG: No
You are given an integer array nums
and two integers cost1
and cost2
. You are allowed to perform either of the following operations any number of times:
- Choose an index
i
fromnums
and increasenums[i]
by1
for a cost ofcost1
. - Choose two different indices
i
,j
, fromnums
and increasenums[i]
andnums[j]
by1
for a cost ofcost2
.
Return the minimum cost required to make all elements in the array equal*.*
Since the answer may be very large, return it modulo 109 + 7
.
Example 1:
Input: nums = [4,1], cost1 = 5, cost2 = 2
Output: 15
Explanation:
The following operations can be performed to make the values equal:
- Increase
nums[1]
by 1 for a cost of 5.nums
becomes[4,2]
. - Increase
nums[1]
by 1 for a cost of 5.nums
becomes[4,3]
. - Increase
nums[1]
by 1 for a cost of 5.nums
becomes[4,4]
.
The total cost is 15.
Example 2:
Input: nums = [2,3,3,3,5], cost1 = 2, cost2 = 1
Output: 6
Explanation:
The following operations can be performed to make the values equal:
- Increase
nums[0]
andnums[1]
by 1 for a cost of 1.nums
becomes[3,4,3,3,5]
. - Increase
nums[0]
andnums[2]
by 1 for a cost of 1.nums
becomes[4,4,4,3,5]
. - Increase
nums[0]
andnums[3]
by 1 for a cost of 1.nums
becomes[5,4,4,4,5]
. - Increase
nums[1]
andnums[2]
by 1 for a cost of 1.nums
becomes[5,5,5,4,5]
. - Increase
nums[3]
by 1 for a cost of 2.nums
becomes[5,5,5,5,5]
.
The total cost is 6.
Example 3:
Input: nums = [3,5,3], cost1 = 1, cost2 = 3
Output: 4
Explanation:
The following operations can be performed to make the values equal:
- Increase
nums[0]
by 1 for a cost of 1.nums
becomes[4,5,3]
. - Increase
nums[0]
by 1 for a cost of 1.nums
becomes[5,5,3]
. - Increase
nums[2]
by 1 for a cost of 1.nums
becomes[5,5,4]
. - Increase
nums[2]
by 1 for a cost of 1.nums
becomes[5,5,5]
.
The total cost is 4.
Constraints:
1 <= nums.length <= 105
1 <= nums[i] <= 106
1 <= cost1 <= 106
1 <= cost2 <= 106
- 1. How can you determine the minimum cost if you know the maximum value in the array once all values are made equal?
- 2. If
cost2 > cost1 * 2
, we should just usecost1
to change all the values to the maximum one. - 3. Otherwise, it's optimal to choose the smallest two values and use
cost2
to increase both of them. - 4. Since the maximum value is known, calculate the required increases to equalize all values, instead of naively simulating the operations.
- 5. There are not a lot of candidates for the maximum; we can try all of them and choose which uses the minimum number of operations.
class Solution {
public:
int minCostToEqualizeArray(vector<int>& nums, int cost1, int cost2) {
}
};
class Solution {
public int minCostToEqualizeArray(int[] nums, int cost1, int cost2) {
}
}
class Solution:
def minCostToEqualizeArray(self, nums: List[int], cost1: int, cost2: int) -> int: