[ Index | Exercise 8.3 | Exercise 8.5 ]
Objectives:
- Managing what happens at the
yield
statements
Files Modified: follow.py
, cofollow.py
A common question concerning generators is their lifetime and garbage
collection. For example, the follow()
generator runs forever in
an infinite while
loop. What happens if the iteration loop that's
driving it stops? Also, is there anyway to prematurely terminate the
generator?
Modify the follow()
function so that all of the code is enclosed in
a try-except
block like this:
def follow(filename):
try:
with open(filename,'r') as f:
f.seek(0,os.SEEK_END)
while True:
line = f.readline()
if line == '':
time.sleep(0.1) # Sleep briefly to avoid busy wait
continue
yield line
except GeneratorExit:
print('Following Done')
Now, try a few experiments:
>>> from follow import follow
>>> # Experiment: Garbage collection of a running generator
>>> f = follow('Data/stocklog.csv')
>>> next(f)
'"MO",70.29,"6/11/2007","09:30.09",-0.01,70.25,70.30,70.29,365314\n'
>>> del f
Following Done
>>> # Experiment: Closing a generator
>>> f = follow('Data/stocklog.csv')
>>> for line in f:
print(line,end='')
if 'IBM' in line:
f.close()
"VZ",42.91,"6/11/2007","09:34.28",-0.16,42.95,42.91,42.78,210151
"HPQ",45.76,"6/11/2007","09:34.29",0.06,45.80,45.76,45.59,257169
"GM",31.45,"6/11/2007","09:34.31",0.45,31.00,31.50,31.45,582429
...
"IBM",102.86,"6/11/2007","09:34.44",-0.21,102.87,102.86,102.77,147550
Following Done
>>> for line in f:
print(line, end='') # No output: generator is done
>>>
In these experiments you can see that a GeneratorExit
exception is
raised when a generator is garbage-collected or explicitly closed via
its close()
method.
One additional area of exploration is whether or not you can resume iteration on a generator if you break out of a for-loop. For example, try this:
>>> f = follow('Data/stocklog.csv')
>>> for line in f:
print(line,end='')
if 'IBM' in line:
break
"CAT",78.36,"6/11/2007","09:37.19",-0.16,78.32,78.36,77.99,237714
"VZ",42.99,"6/11/2007","09:37.20",-0.08,42.95,42.99,42.78,268459
...
"IBM",102.91,"6/11/2007","09:37.31",-0.16,102.87,102.91,102.77,190859
>>> # Resume iteration
>>> for line in f:
print(line,end='')
if 'IBM' in line:
break
"AA",39.58,"6/11/2007","09:39.28",-0.08,39.67,39.58,39.31,243159
"HPQ",45.94,"6/11/2007","09:39.29",0.24,45.80,45.94,45.59,408919
...
"IBM",102.95,"6/11/2007","09:39.44",-0.12,102.87,102.95,102.77,225350
>>> del f
Following Done
>>>
In general, you can break out of running iteration and resume it later if you need to. You just need to make sure the generator object isn't forcefully closed or garbage collected somehow.
In the file cofollow.py
, you created a coroutine printer()
. Modify the
code to catch and report exceptions like this:
# cofollow.py
...
@consumer
def printer():
while True:
try:
item = yield
print(item)
except Exception as e:
print('ERROR: %r' % e)
Now, try an experiment:
>>> from cofollow import printer
>>> p = printer()
>>> p.send('hello')
hello
>>> p.send(42)
42
>>> p.throw(ValueError('It failed'))
ERROR: ValueError('It failed',)
>>> try:
int('n/a')
except ValueError as e:
p.throw(e)
ERROR: ValueError("invalid literal for int() with base 10: 'n/a'",)
>>>
Notice how the running generator is not terminated by the exception. This
is merely allowing the yield
statement to signal an error instead of
receiving a value.
[ Solution | Index | Exercise 8.3 | Exercise 8.5 ]
>>>
Advanced Python Mastery
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A course by dabeaz
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