Load the OAuth2 server code

[steveconners]

We'd like to move the server code out of the API repository. For the time being, it is a distinct application.

[slifty]

@ashaar364 Maybe we can chat on our call tomorrow about the OAuth2 server code that has been written so far to make sure I don't miss anything here!

My understanding is that the OAuth server code is in the Google Oauth sample login source code along with code to handle google and salesforce login.

[ashaar364]

@slifty No that is not correct. These are two type of code one is client and one is server. Google and Sales force code is the client code. The client code connects to the server and authenticate the user and generate the token. In that case Google and Sales Force have the server and we access them. Where as the server code is Pathway server code, In our server, we maintain all the creation and distribution of the token. Ideally we will be providing all the three login facility. User should be able to access our API, if he holds the google account or sales force account or s/he is already registered with us.

[imlab10]

Ashaar is correct. It should work as what Ashaar described. That's how
OAuth should work.

Thanks
Rodger

On Thu, Jul 9, 2015 at 7:13 PM, Ashaar notifications@github.com wrote:

@slifty https://github.com/slifty No that is not correct. These are two
type of code one is client and one is server. Google and Sales force code
is the client code. The client code connects to the server and authenticate
the user and generate the token. In that case Google and Sales Force have
the server and we access them. Where as the server code is Pathway server
code, In our server, we maintain all the creation and distribution of the
token. Ideally we will be providing all the three login facility. User
should be able to access our API, if he holds the google account or sales
force account or s/he is already registered with us.

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Reply to this email directly or view it on GitHub
#1 (comment).

[kfogel]

nod Just to confirm: both @slifty and I have read this & it makes sense. Thanks, @ashaar364 and @imlab10 !