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Kmedian Analysis.py
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"""
K median Analysis
@author: Siddhant Agarwal
"""
import numpy as np
def Kmedian(data, k, random_state = 0):
'''
Input -
data: The data in an array and not as a dataframe
k: the number of clusters you require
Output - depending on the breaking condition
mu_new or mu: centroids of the clusters
assignment_new or assignment: the cluster assignment for each data point
J_new or J_old: The loss value corresponding to a particular k (number of clusters)
'''
np.random.seed(random_state)
# Randomly initializing cluster centroid from the data
mu = data[np.random.randint(data.shape[0], size = k),:]
#Taking 1000 iterations as a maximum iterations if the algorithm doesn't converge
for a in range(1000):
distance_vector = np.zeros((k,data.shape[0]))
for i in range(k):
for j in range(data.shape[0]):
#Calculating the manhattan distance of culster centroid with the data points
distance_vector[i,j] = np.abs(mu[i] - data[j]).sum()
#Assigning data points to the cluster based on its minimum distance from the centroid
assignment = np.argmin(distance_vector, axis = 0)
#Separating the index of the data points according to the cluster it is assigned
index_cluster = [np.argwhere(i==assignment) for i in np.unique(assignment)]
idx = []
for i in range(k):
idx1 = []
for j in range(len(index_cluster[i])):
idx1.append(index_cluster[i][j][0])
idx.append(np.array(idx1))
idx = np.array(idx)
J_old = 0
#Calculating cost function for the old assignment
for i in range(k):
for j in range(len(index_cluster[i])):
J_old += np.abs(mu[i] - data[index_cluster[i][j][0]]).sum()
J_old = J_old/data.shape[0]
sorted_idx = [] #Sorting in ascending order based on the distance from the centroid
#Calculating new centroid
mu_new = np.zeros((k,data.shape[1]))
for i in range(k):
sorted_idx.append(idx[i][np.argsort(distance_vector[i, idx[i]])])
mu_new[i, :] = np.median(data[sorted_idx[i]], axis = 0)
distance_vector_new = np.zeros((k,data.shape[0]))
for i in range(k):
for j in range(data.shape[0]):
#Calculating the manhattan distance of culster centroid with the data points
distance_vector_new[i,j] = np.abs(mu_new[i] - data[j]).sum()
#Assigning data points to the cluster based on its minimum distance from the centroid
assignment_new = np.argmin(distance_vector_new, axis = 0)
#Separating the index of the data points according to the cluster it is assigned
index_cluster_new = [np.argwhere(i==assignment_new) for i in np.unique(assignment_new)]
J_new = 0
#Calculating cost function for the old assignment
for i in range(k):
try:
for j in range(len(index_cluster_new[i])):
J_new += np.abs(mu_new[i]-data[index_cluster_new[i][j][0]]).sum()
except:
print('empty cluster')
finally:
J_new += 0
J_new = J_new/data.shape[0]
#Condition to break the initial for loop, convergence is achieved if the difference between the old and new cost function is greater than 0 and less than 1
if (J_old - J_new) >=0 and (J_old - J_new) <1:
return mu_new, assignment_new, J_new
break
#If old - new cost function is less than 0 then new cost is higher than the old cost thus return the older assignment
elif (J_old - J_new) <0:
return mu, assignment, J_old
break
#Here convergence is not achieved thus assign new assignment as old assignment and continue till convergence is achieved
else:
mu = mu_new
return mu_new, assignment_new, J_new