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Copy path102.二叉树的层序遍历.go
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102.二叉树的层序遍历.go
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/*
* @lc app=leetcode.cn id=102 lang=golang
*
* [102] 二叉树的层序遍历
*
* https://leetcode-cn.com/problems/binary-tree-level-order-traversal/description/
*
* algorithms
* Medium (64.18%)
* Likes: 806
* Dislikes: 0
* Total Accepted: 267.2K
* Total Submissions: 416.2K
* Testcase Example: '[3,9,20,null,null,15,7]'
*
* 给你一个二叉树,请你返回其按 层序遍历 得到的节点值。 (即逐层地,从左到右访问所有节点)。
*
*
*
* 示例:
* 二叉树:[3,9,20,null,null,15,7],
*
*
* 3
* / \
* 9 20
* / \
* 15 7
*
*
* 返回其层序遍历结果:
*
*
* [
* [3],
* [9,20],
* [15,7]
* ]
*
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func levelOrder(root *TreeNode) [][]int {
if root == nil {
return [][]int{}
}
var res [][]int
// 将根节点放在二维列表中
q := []*TreeNode{root}
// 遍历左右节点,左右兄弟节点放在同一层
for len(q) > 0 {
level := []int{}
for _, x := range q {
q = q[1:]
if x.Left != nil {
q = append(q, x.Left)
}
if x.Right != nil {
q = append(q, x.Right)
}
level = append(level, x.Val)
}
res = append(res, level)
}
return res
}
// @lc code=end