Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
The number of elements initialized in nums1 and nums2 are m and n respectively.
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
/**
* @param {number[]} nums1
* @param {number} m
* @param {number[]} nums2
* @param {number} n
* @return {void} Do not return anything, modify nums1 in-place instead.
*/
var merge = function (nums1, m, nums2, n) {
var firstIndex = 0;
var secondIndex = 0;
while (secondIndex !== n && firstIndex - secondIndex < m) {
if (nums1[firstIndex] > nums2[secondIndex]) {
for (let i = nums1.length - 1; i !== firstIndex; --i) {
nums1[i] = nums1[i - 1];
}
nums1[firstIndex] = nums2[secondIndex];
console.log(nums1);
++firstIndex;
++secondIndex;
} else {
++firstIndex;
}
}
if (secondIndex !== n) {
for (secondIndex; secondIndex < n; ++secondIndex) {
nums1[firstIndex++] = nums2[secondIndex];
}
}
};