An integer has sequential digits if and only if each digit in the number is one more than the previous digit.
Return a sorted list of all the integers in the range [low, high] inclusive that have sequential digits.Example 1:
Input: low = 100, high = 300
Output: [123,234]
Example 2:
Input: low = 1000, high = 13000
Output: [1234,2345,3456,4567,5678,6789,12345]
class Solution {
public List<Integer> sequentialDigits(int low, int high) {
String s = "123456789";
List<Integer> ans = new ArrayList();
for(int i = 2; i < 10; ++i) {
for(int j = 0; i + j < 10; ++j) {
int t = Integer.parseInt(s.substring(j, i + j));
if(t >= low) {
if(t <= high) {
ans.add(t);
} else {
return ans;
}
}
}
}
return ans;
}
}