169.majority-element.md

题目地址

https://leetcode.com/problems/majority-element/description/

题目描述

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.

You may assume that the array is non-empty and the majority element always exist in the array.

Example 1:

Input: [3,2,3]
Output: 3
Example 2:

Input: [2,2,1,1,1,2,2]
Output: 2

思路

符合直觉的做法是利用额外的空间去记录每个元素出现的次数，并用一个单独的变量记录当前出现次数最多的元素。

但是这种做法空间复杂度较高，有没有可能进行优化呢？ 答案就是用"投票算法"。

投票算法的原理是通过不断消除不同元素直到没有不同元素，剩下的元素就是我们要找的元素。

关键点解析

• 投票算法

代码

• 语言支持：JS，Python

Javascript Code:

var majorityElement = function(nums) {
    let count = 1;
    let majority = nums[0];
    for(let i = 1; i < nums.length; i++) {
        if (count === 0) {
            majority = nums[i];
        }
        if (nums[i] === majority) {
            count ++;
        } else {
            count --;
        }
    }
    return majority;
};

Python Code:

class Solution:
    def majorityElement(self, nums: List[int]) -> int:
        count, majority = 1, nums[0]
        for num in nums[1:]:
            if count == 0:
                majority = num
            if num == majority:
                count += 1
            else:
                count -= 1
        return majority