难度: Easy
原题连接
内容描述
Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example:
Input: 19
Output: true
Explanation:
12 + 92 = 82
82 + 22 = 68
62 + 82 = 100
12 + 02 + 02 = 1
思路 1 - 时间复杂度: O(1)- 空间复杂度: O(1)******
sb题没什么好说的, beats 98.71%
class Solution:
def isHappy(self, n):
"""
:type n: int
:rtype: bool
"""
def squareSum(num):
res = 0
for i in str(num):
res += int(i) ** 2
return res
lookup = set()
happy_sum = squareSum(n)
while happy_sum not in lookup and happy_sum != 1:
lookup.add(happy_sum)
happy_sum = squareSum(happy_sum)
return True if happy_sum == 1 else False
可以看看这两篇post
会有一个更深的认知