难度: Medium
原题连接
内容描述
Implement a trie with insert, search, and startsWith methods.
Example:
Trie trie = new Trie();
trie.insert("apple");
trie.search("apple"); // returns true
trie.search("app"); // returns false
trie.startsWith("app"); // returns true
trie.insert("app");
trie.search("app"); // returns true
Note:
You may assume that all inputs are consist of lowercase letters a-z.
All inputs are guaranteed to be non-empty strings.
思路 1 - 时间复杂度: O(N)- 空间复杂度: O(N)******
这个Python实现也太精美了吧,谷歌复写之
然后还unlock了一个solution,to read
Trie整个都需要 to read,精美,可爱😊
class TrieNode(object):
def __init__(self):
"""
Initialize your data structure here.
"""
self.childs = dict()
self.isWord = False
class Trie(object):
def __init__(self):
self.root = TrieNode()
def insert(self, word):
"""
Inserts a word into the trie.
:type word: str
:rtype: void
"""
node = self.root
for letter in word:
child = node.childs.get(letter)
if child is None:
child = TrieNode()
node.childs[letter] = child
node = child
node.isWord = True
def search(self, word):
"""
Returns if the word is in the trie.
:type word: str
:rtype: bool
"""
node = self.root
for i in word:
child = node.childs.get(i)
if child is None:
return False
node = child
return node.isWord
def startsWith(self, prefix):
"""
Returns if there is any word in the trie
that starts with the given prefix.
:type prefix: str
:rtype: bool
"""
node = self.root
for letter in prefix:
child = node.childs.get(letter)
if child is None:
return False
node = child
return True
# Your Trie object will be instantiated and called as such:
# trie = Trie()
# trie.insert("somestring")
# trie.search("key")