难度: Easy
原题连接
内容描述
Consider all the leaves of a binary tree. From left to right order, the values of those leaves form a leaf value sequence.
For example, in the given tree above, the leaf value sequence is (6, 7, 4, 9, 8).
Two binary trees are considered leaf-similar if their leaf value sequence is the same.
Return true if and only if the two given trees with head nodes root1 and root2 are leaf-similar.
Note:
Both of the given trees will have between 1 and 100 nodes.
思路 1 - 时间复杂度: O(N)- 空间复杂度: O(N)******
先递归找到两颗树的叶子结点集合,再比较是否相等。beats 100%
class Solution(object):
def leafSimilar(self, root1, root2):
"""
:type root1: TreeNode
:type root2: TreeNode
:rtype: bool
"""
def findleaf(root):
if not root:
return []
if not root.left and not root.right:
return [root.val]
return findleaf(root.left) + findleaf(root.right)
return findleaf(root1) == findleaf(root2)