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solution.java
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solution.java
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import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
public class solution {
// Complete the misereNim function below.
static String misereNim(int[] s) {
int n = s.length;
// if there is only 1 pile AND it has more than 1 element => First player wins
if (n == 1) {
return s[0] > 1 ? "First" : "Second";
}
int total = s[0];
int xor = s[0];
for (int i = 1; i < n; i++) {
total += s[i];
xor ^= s[i];
}
/*
* If sum of all stones equals the total piles, all piles have a single (1)
* stone. For even number of piles, first player will always win.
*/
if (total == n) {
return total % 2 == 0 ? "First" : "Second";
}
/*
* For all other cases, the xor value determines winner. If xor value = 0, then
* second player will always win as all piles (stones) can be paired.
*/
return xor > 0 ? "First" : "Second";
}
private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) throws IOException {
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
int t = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
for (int tItr = 0; tItr < t; tItr++) {
int n = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
int[] s = new int[n];
String[] sItems = scanner.nextLine().split(" ");
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
for (int i = 0; i < n; i++) {
int sItem = Integer.parseInt(sItems[i]);
s[i] = sItem;
}
String result = misereNim(s);
bufferedWriter.write(result);
bufferedWriter.newLine();
}
bufferedWriter.close();
scanner.close();
}
}