16_Quiz.txt

1. Select the code which uses an outer join correctly.

 SELECT teacher.name, dept.name FROM teacher LEFT OUTER JOIN dept ON (teacher.dept = dept.id)

2. Select the correct statement that shows the name of department which employs Cutflower -

 SELECT dept.name FROM teacher JOIN dept ON (dept.id = teacher.dept) WHERE teacher.name = 'Cutflower'

3. Select out of following the code which uses a JOIN to show a list of all the departments and number of employed teachers

 SELECT dept.name, COUNT(teacher.name) FROM teacher RIGHT JOIN dept ON dept.id = teacher.dept GROUP BY dept.name

4. Using SELECT name, dept, COALESCE(dept, 0) AS result FROM teacher on teacher table will:

display 0 in result column for all teachers without department

5. Query:

SELECT name,
       CASE WHEN phone = 2752 THEN 'two'
            WHEN phone = 2753 THEN 'three'
            WHEN phone = 2754 THEN 'four'
            END AS digit
  FROM teacher
shows following 'digit':

'four' for Throd

Table-A
Shrivell    Computing
Throd	    Computing
Splint	    Computing
Spiregrain	Other
Cutflower	Other
Deadyawn	Other

6. Select the result that would be obtained from the following code:
 
  SELECT name, 
      CASE 
       WHEN dept 
        IN (1) 
        THEN 'Computing' 
       ELSE 'Other' 
      END 
  FROM teacher

Table-A
Shrivell	Computing
Throd	Computing
Splint	Computing
Spiregrain	Other
Cutflower	Other
Deadyawn	Other