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Depending on your culture, you may have problem since the float are entered with '.' for separator #60

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Philippe-Laval opened this issue Jul 27, 2023 · 0 comments

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@Philippe-Laval
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When loading data in the examples, depending on your culture, you may have problem since the float are entered with '.' for separator.
You have to add CultureInfo.InvariantCulture like in this exemple :

float f = float.Parse(s, CultureInfo.InvariantCulture);

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