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// Given an integer array nums where every element appears three times except for one, which appears exactly once. Find the single element and return it.
// You must implement a solution with a linear runtime complexity and use only constant extra space.
// Example 1:
// Input: nums = [2,2,3,2]
// Output: 3
// Example 2:
// Input: nums = [0,1,0,1,0,1,99]
// Output: 99
const singleNumber = nums => {
nums.sort()
for (let i = 0; i < nums.length; i += 3) {
if (nums[i] !== nums[i + 1]) return nums[i]
}
}
// const singleNumber = nums => {
// for (let key of nums) {
// if (nums.indexOf(key) === nums.lastIndexOf(key)) return key