2215. Find the Difference of Two Arrays.js

// Given two 0-indexed integer arrays nums1 and nums2, return a list answer of size 2 where:

// answer[0] is a list of all distinct integers in nums1 which are not present in nums2.
// answer[1] is a list of all distinct integers in nums2 which are not present in nums1.
// Note that the integers in the lists may be returned in any order.

// Example 1:

// Input: nums1 = [1,2,3], nums2 = [2,4,6]
// Output: [[1,3],[4,6]]
// Explanation:
// For nums1, nums1[1] = 2 is present at index 0 of nums2, whereas nums1[0] = 1 and nums1[2] = 3 are not present in nums2. Therefore, answer[0] = [1,3].
// For nums2, nums2[0] = 2 is present at index 1 of nums1, whereas nums2[1] = 4 and nums2[2] = 6 are not present in nums2. Therefore, answer[1] = [4,6].
// Example 2:

// Input: nums1 = [1,2,3,3], nums2 = [1,1,2,2]
// Output: [[3],[]]
// Explanation:
// For nums1, nums1[2] and nums1[3] are not present in nums2. Since nums1[2] == nums1[3], their value is only included once and answer[0] = [3].
// Every integer in nums2 is present in nums1. Therefore, answer[1] = [].

const findDifference = (nums1, nums2) => {
	const set1 = new Set(nums1)
	const set2 = new Set(nums2)

	const diff1 = [...set1].filter(num => !set2.has(num))
	const diff2 = [...set2].filter(num => !set1.has(num))

	return [diff1, diff2]
}