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SerializeAndDeserializeBST.js
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96 lines (92 loc) · 2.21 KB
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// Source : https://leetcode.com/problems/serialize-and-deserialize-bst/
// Author : avebeatrix
// Date : 2022-09-04
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* Encodes a tree to a single string.
*
* @param {TreeNode} root
* @return {string}
*/
var serialize = function(root) {
if (!root) {
return '';
}
let result = '';
let addNode = (node) => {
result += node.val;
if (node.left) {
result += 'L';
addNode(node.left);
}
if (node.right) {
result += 'R';
addNode(node.right);
}
result += 'U';
}
addNode(root);
return result;
};
/**
* Decodes your encoded data to tree.
*
* @param {string} data
* @return {TreeNode}
*/
var deserialize = function(data) {
if (!data) {
return null;
}
let val = parseInt(data);
let tree = {
val: val,
left: null,
right: null,
}
let pointer = val.toString().length;
let node = tree;
let stack = [node];
while (pointer < data.length) {
node = stack[stack.length - 1];
if (data[pointer] === 'L') {
pointer++;
let val = parseInt(data.slice([pointer]));
node.left = {
val:val,
left: null,
right: null,
}
node = node.left;
stack.push(node);
pointer += val.toString().length;
} else if (data[pointer] === 'R') {
pointer++;
let val = parseInt(data.slice([pointer]));
node.right = {
val: val,
left: null,
right: null,
}
node = node.right;
stack.push(node);
pointer += val.toString().length;
} else if (data[pointer] === 'U') {
stack.pop();
pointer++;
}
}
return tree;
};
/**
* Your functions will be called as such:
* deserialize(serialize(root));
*/
let tree = deserialize('1L2L4UUR3R5UUU');
console.log(serialize(tree));