20180530Notes.txt

Everyone's notes/code snippets from the call will go here

### Bonnie's code
import os

def getDirectory():
    targetDirectory = ('Enter the directory path: ')
    return targetDirectory

def validateExtension(filename):
    print("All files have extensions")

def validateFileSize(filename):
    print("All files bigger than 0 bytes")

def findHiddenFiles(filename):
    print("No hidden files found")
    
def findWhiteSpace(filename):
    print("No filenames contain whitespace")
    
targetDirectory = getDirectory()

filenames = os.listdir(targetDirectory)
print(filenames)

for filename in filenames:
    validateExtension(filename)
    validateFileSize(filename)
    findHiddenFiles(filename)
    findWhiteSpace(filename)
print("Done!")


### Shira and Maggie's code
sourcefile = input('Enter the directory name or file name:')

# Does this check if sourcefile is a directory or a single file? source: https://docs.python.org/3.0/library/stat.html
import os, sys
from stat import *

def walktree(top, callback):
    '''recursively descend the directory tree rooted at top,
       calling the callback function for each regular file'''

    for f in os.listdir(top):
        pathname = os.path.join(top, f)
        mode = os.stat(pathname)[ST_MODE]
        if S_ISDIR(mode):
            # It's a directory, recurse into it
            walktree(pathname, callback)
        elif S_ISREG(mode):
            # It's a file, call the callback function
            callback(pathname)
        else:
            # Unknown file type, print a message
            print('Skipping %s' % pathname)

for file in sourcefile:

# below assumes that all file names are separated with a comma
# the below pulls out the file extension and checks that it is valid, i.e. between 2 and 4 characters long

try:
  findext = sourcefile.find('.')
  ext = sourcefile.find(',',findext) #how to find end of a single file name, if no comma is present to separate multiple files
  fileext = sourcefile[findext:ext]
    if
      fileext == [2:4]
    elseif:
        print "Error: not a valid file extension"
   print fileext
except:
    print "Error: file does not have a file extension"

# the below searches for whitespace in filenames

space = sourcefile.find(' ')
    ' ' in sourcefile:
        if True:
        if False:

#finds whitespace in filenames with regular expressions

import re
try:
    sp = re.compile('\s')
    findsp = sourcefile.find(sp)
    print "Error: file name contains whitespace"


# the below tries to check the file size in bytes and print the file size. If the file is 0 bytes, it returns an error. Source: https://stackoverflow.com/questions/6591931/getting-file-size-in-python

try:
    def getSize(sourcefile):
    st = os.stat(sourcefile)
        if st.st_size == 0
            print "Error: file is 0 bytes"
        elseif:
            print st.st_size
            
            
### farrell's code
#!/usr/bin/env python3
# attempt at reporting whether or not files in a directory have extensions or not.

import os, csv, argparse

parser = argparse.ArgumentParser()
parser.add_argument("-o","--output", help="Path to and filename for the CSV to create.")
parser.add_argument("-d","--directory", help="Path to input directory.")
args = parser.parse_args()

if args.output:
	global csvOut
	csvOut = args.output
if args.directory:
	global inputDir
	inputDir = args.directory

with open (csvOut, 'w') as f: #'wb' worked in python 2.7. Does not in 3.5...somethign to do with 'wb' being write+binary, so expecting binary values not strings.
	writer = csv.writer(f)
	writer.writerow(['path','filename','extension','extPassFail'])
	for path, dirs, files in os.walk(inputDir):
		for filename in files:
			extension = os.path.splitext(filename)[1]
			if extension == "":
				extPassFail = "fail"
			else:
				extPassFail = "pass"
			writer.writerow([path,filename,extension,extPassFail])