How to map typedef array

[luxingxiao]

C language header:
typedef uint8_t DDS_XTypes_NameHash[4];

[saudet]

It's typically easiest to consider that the same as a char*.

[luxingxiao]

:(

.put(new Info("DDS_XTypes_NameHash").cppTypes("char*"))

error: incompatible types in assignment of ‘char*’ to ‘DDS_XTypes_NameHash’ {aka ‘unsigned char [4]’}
4293 | ptr->name_hash = (char*)ptr0;
| ~~~~~~~~~~~~~~~^~~~~~~~~~~~~
error: ISO C++ forbids casting to an array type ‘DDS_XTypes_QualifiedTypeName’ {aka ‘char [257]’}
8310 | DDS_XTypes_QualifiedTypeName rval = (DDS_XTypes_QualifiedTypeName)ptr->annotation_name;

[saudet]

We can't cast a pointer to an array, no. In a case like that, we might need to write some custom Java code like this:
https://github.com/bytedeco/javacpp/wiki/Mapping-Recipes#mapping-a-declaration-to-custom-code

[saudet]

Try to annotate with @MemberGetter like this:
https://github.com/bytedeco/javacpp/wiki/Mapping-Recipes#mapping-a-declaration-to-custom-code