Reverse bits of a given 32 bits unsigned integer.
Note:
- Note that in some languages, such as Java, there is no unsigned integer type. In this case, both input and output will be given as a signed integer type. They should not affect your implementation, as the integer's internal binary representation is the same, whether it is signed or unsigned.
- In Java, the compiler represents the signed integers using 2's complement notation. Therefore, in Example 2 above, the input represents the signed integer -3 and the output represents the signed integer -1073741825.
n&1
will give us lsb.- we will shift lsb to left by
31-i
bits and it will be our reverseLsb. - we will or reverseLsb with result.
- shift n by 1 to right.
- Reference Video
class Solution{
public:
uint32_t reverseBits(uint32_t n){
int res = 0;
for (int i = 0; i < 32; i++){
int lsb = n & 1;
int reverseLsb = lsb << (31 - i);
res |= reverseLsb;
n = n >> 1;
}
return res;
}
};