diff --git a/lab-sql-joins.sql b/lab-sql-joins.sql
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+USE sakila;
+
+-- Write SQL queries to perform the following tasks using the Sakila database:
+
+		-- 1. List the number of films per category.
+SELECT * FROM film;   -- film_id- PK
+SELECT * FROM film_category;  -- film_id - PK, FK
+							  -- category_id PK, FK
+SELECT * FROM category;  -- category_id - PK
+
+SELECT 
+    c.name AS category_name, COUNT(f.film_id) AS film_count
+FROM
+    category c
+        JOIN
+    film_category fc ON c.category_id = fc.category_id
+        JOIN
+    film f ON fc.film_id = f.film_id
+GROUP BY c.name
+ORDER BY film_count DESC;
+        
+		-- 2. Retrieve the store ID, city, and country for each store.
+SELECT 
+    s.store_id, ci.city, c.country
+FROM
+    store s
+        JOIN
+    address a ON s.address_id = a.address_id
+        JOIN
+    city ci ON ci.city_id = a.city_id
+        JOIN
+    country c ON c.country_id = ci.country_id;
+
+		-- 3. Calculate the total revenue generated by each store in dollars.
+SELECT 
+    *
+FROM
+    payment;
+SELECT 
+    st.store_id, SUM(p.amount) AS total_revenue
+FROM
+    store st
+        JOIN
+    staff s ON st.store_id = s.store_id
+        JOIN
+    payment p ON s.staff_id = p.staff_id
+GROUP BY st.store_id;
+
+		-- 4. Determine the average running time of films for each category.
+SELECT c.name AS genre,
+AVG(f.length) AS avg_movie_duration
+FROM category c
+JOIN film_category fc ON fc.category_id = c.category_id 
+JOIN film f ON f.film_id = fc.film_id
+GROUP BY c.name
+ORDER BY avg_movie_duration ASC;
+
+-- Bonus:
+
+		-- Identify the film categories with the longest average running time.
+SELECT c.name AS genre,
+MAX(f.length) AS longest_movie_duration
+FROM category c
+JOIN film_category fc ON fc.category_id = c.category_id 
+JOIN film f ON f.film_id = fc.film_id
+GROUP BY c.name
+ORDER BY longest_movie_duration ASC;
+
+		-- Display the top 10 most frequently rented movies in descending order.
+SELECT f.title AS movie_name,
+COUNT(r.rental_id) AS frequently_rented
+FROM film f
+JOIN inventory i ON i.film_id = f.film_id
+JOIN rental r ON i.inventory_id = r.inventory_id
+GROUP BY f.title
+ORDER BY frequently_rented DESC 
+LIMIT 10;
+
+		-- Determine if "Academy Dinosaur" can be rented from Store 1.
+SELECT f.title, s.store_id,
+COUNT(i.inventory_id) AS available_copies
+FROM film f
+JOIN inventory i ON i.film_id = f.film_id
+JOIN store s ON s.store_id = i.store_id
+WHERE title = 'Academy Dinosaur' AND s.store_id = 1
+GROUP BY f.title;
+
+		/* Provide a list of all distinct film titles, along with their availability status in the inventory.
+		   Include a column indicating whether each title is 'Available' or 'NOT available.' 
+           Note that there are 42 titles that are not in the inventory, 
+           and this information can be obtained using a CASE statement combined with IFNULL."
+		*/
+SELECT f.title,
+CASE 
+	WHEN COUNT(i.inventory_id) > 0 THEN 'Available'
+    ELSE 'NOT available'
+END AS availability_status
+FROM film f
+LEFT JOIN
+inventory i ON f.film_id = i.film_id
+GROUP BY
+f.title
+ORDER BY 
+f.title;
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