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binary-tree-right-side-view.go
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/
binary-tree-right-side-view.go
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package main
import (
"fmt"
. "github.com/dimaglushkov/solutions/ADS/tree"
)
// source: https://leetcode.com/problems/binary-tree-right-side-view/
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
type elem struct {
h int
*TreeNode
}
type queue []elem
func (q *queue) push(x elem) {
*q = append(*q, x)
}
func (q *queue) pop() elem {
x := (*q)[0]
*q = (*q)[1:]
return x
}
func rightSideView(root *TreeNode) []int {
if root == nil {
return nil
}
m := make(map[int]int)
q := new(queue)
q.push(elem{0, root})
for len(*q) > 0 {
x := q.pop()
m[x.h] = x.Val
if x.Left != nil {
q.push(elem{x.h + 1, x.Left})
}
if x.Right != nil {
q.push(elem{x.h + 1, x.Right})
}
}
ans := make([]int, len(m))
for k, v := range m {
ans[k] = v
}
return ans
}
func main() {
testCases := []struct {
root *TreeNode
want []int
}{
{
root: NewTreeNode(nil),
want: []int{},
},
}
successes := 0
for _, tc := range testCases {
x := rightSideView(tc.root)
status := "ERROR"
if fmt.Sprint(x) == fmt.Sprint(tc.want) {
status = "OK"
successes++
}
fmt.Println(status, " Expected: ", tc.want, " Actual: ", x)
}
if l := len(testCases); successes == len(testCases) {
fmt.Printf("===\nSUCCESS: %d of %d tests ended successfully\n", successes, l)
} else {
fmt.Printf("===\nFAIL: %d tests failed\n", l-successes)
}
}