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Solution.sql
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Solution.sql
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/**
* Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking.
* Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.
*
* +----+-------+
* | Id | Score |
* +----+-------+
* | 1 | 3.50 |
* | 2 | 3.65 |
* | 3 | 4.00 |
* | 4 | 3.85 |
* | 5 | 4.00 |
* | 6 | 3.65 |
* +----+-------+
* For example, given the above Scores table, your query should generate the following report (order by highest score):
*
* +-------+------+
* | Score | Rank |
* +-------+------+
* | 4.00 | 1 |
* | 4.00 | 1 |
* | 3.85 | 2 |
* | 3.65 | 3 |
* | 3.65 | 3 |
* | 3.50 | 4 |
* +-------+------+
*/
select s0.Score, case when number is null then 1 else number end as Rank from Scores as s0
left join
(select id1, count(distinct score2) + 1 as number from (
select s1.score as score1, s2.score as score2, s1.Id as id1 from Scores as s1 cross join Scores as s2
where s1.score < s2.score
) as joined_scores group by id1) as tmp
on s0.id = tmp.id1 order by s0.Score desc;