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rake.py
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rake.py
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# Implementation of RAKE - Rapid Automatic Keyword Extraction algorithm
# as described in:
# Rose, S., D. Engel, N. Cramer, and W. Cowley (2010).
# Automatic keyword extraction from individual documents.
# In M. W. Berry and J. Kogan (Eds.), Text Mining: Applications and Theory.unknown: John Wiley and Sons, Ltd.
#
# NOTE: The original code (from https://github.com/aneesha/RAKE)
# has been extended by a_medelyan (zelandiya)
# with a set of heuristics to decide whether a phrase is an acceptable candidate
# as well as the ability to set frequency and phrase length parameters
# important when dealing with longer documents
#
# NOTE 2: The code published by a_medelyan (https://github.com/zelandiya/RAKE-tutorial)
# has been additionally extended by Marco Pegoraro to implement the adjoined candidate
# feature described in section 1.2.3 of the original paper. Note that this creates the
# need to modify the metric for the candidate score, because the adjoined candidates
# have a very high score (because of the nature of the original score metric)
from __future__ import absolute_import
from __future__ import print_function
import re
import operator
import six
from six.moves import range
from collections import Counter
debug = False
test = False
def is_number(s):
try:
float(s) if '.' in s else int(s)
return True
except ValueError:
return False
def load_stop_words(stop_word_file):
"""
Utility function to load stop words from a file and return as a list of words
@param stop_word_file Path and file name of a file containing stop words.
@return list A list of stop words.
"""
stop_words = []
for line in open(stop_word_file):
if line.strip()[0:1] != "#":
for word in line.split(): # in case more than one per line
stop_words.append(word)
return stop_words
def separate_words(text, min_word_return_size):
"""
Utility function to return a list of all words that are have a length greater than a specified number of characters.
@param text The text that must be split in to words.
@param min_word_return_size The minimum no of characters a word must have to be included.
"""
splitter = re.compile('[^a-zA-Z0-9_\\+\\-/]')
words = []
for single_word in splitter.split(text):
current_word = single_word.strip().lower()
# leave numbers in phrase, but don't count as words, since they tend to invalidate scores of their phrases
if len(current_word) > min_word_return_size and current_word != '' and not is_number(current_word):
words.append(current_word)
return words
def split_sentences(text):
"""
Utility function to return a list of sentences.
@param text The text that must be split in to sentences.
"""
sentence_delimiters = re.compile(u'[\\[\\]\n.!?,;:\t\\-\\"\\(\\)\\\'\u2019\u2013]')
sentences = sentence_delimiters.split(text)
return sentences
def build_stop_word_regex(stop_word_list):
stop_word_regex_list = []
for word in stop_word_list:
word_regex = '\\b' + word + '\\b'
stop_word_regex_list.append(word_regex)
stop_word_pattern = re.compile('|'.join(stop_word_regex_list), re.IGNORECASE)
return stop_word_pattern
#
# Function that extracts the adjoined candidates from a list of sentences and filters them by frequency
#
def extract_adjoined_candidates(sentence_list, stoplist, min_keywords, max_keywords, min_freq):
adjoined_candidates = []
for s in sentence_list:
# Extracts the candidates from each single sentence and adds them to the list
adjoined_candidates += adjoined_candidates_from_sentence(s, stoplist, min_keywords, max_keywords)
# Filters the candidates and returns them
return filter_adjoined_candidates(adjoined_candidates, min_freq)
# return adjoined_candidates
#
# Function that extracts the adjoined candidates from a single sentence
#
def adjoined_candidates_from_sentence(s, stoplist, min_keywords, max_keywords):
# Initializes the candidate list to empty
candidates = []
# Splits the sentence to get a list of lowercase words
sl = s.lower().split()
# For each possible length of the adjoined candidate
for num_keywords in range(min_keywords, max_keywords + 1):
# Until the third-last word
for i in range(0, len(sl) - num_keywords):
# Position i marks the first word of the candidate. Proceeds only if it's not a stopword
if sl[i] not in stoplist:
candidate = sl[i]
# Initializes j (the pointer to the next word) to 1
j = 1
# Initializes the word counter. This counts the non-stopwords words in the candidate
keyword_counter = 1
contains_stopword = False
# Until the word count reaches the maximum number of keywords or the end is reached
while keyword_counter < num_keywords and i + j < len(sl):
# Adds the next word to the candidate
candidate = candidate + ' ' + sl[i + j]
# If it's not a stopword, increase the word counter. If it is, turn on the flag
if sl[i + j] not in stoplist:
keyword_counter += 1
else:
contains_stopword = True
# Next position
j += 1
# Adds the candidate to the list only if:
# 1) it contains at least a stopword (if it doesn't it's already been considered)
# AND
# 2) the last word is not a stopword
# AND
# 3) the adjoined candidate keyphrase contains exactly the correct number of keywords (to avoid doubles)
if contains_stopword and candidate.split()[-1] not in stoplist and keyword_counter == num_keywords:
candidates.append(candidate)
return candidates
#
# Function that filters the adjoined candidates to keep only those that appears with a certain frequency
#
def filter_adjoined_candidates(candidates, min_freq):
# Creates a dictionary where the key is the candidate and the value is the frequency of the candidate
candidates_freq = Counter(candidates)
filtered_candidates = []
# Uses the dictionary to filter the candidates
for candidate in candidates:
freq = candidates_freq[candidate]
if freq >= min_freq:
filtered_candidates.append(candidate)
return filtered_candidates
def generate_candidate_keywords(sentence_list, stopword_pattern, stop_word_list, min_char_length=1, max_words_length=5,
min_words_length_adj=1, max_words_length_adj=1, min_phrase_freq_adj=2):
phrase_list = []
for s in sentence_list:
tmp = re.sub(stopword_pattern, '|', s.strip())
phrases = tmp.split("|")
for phrase in phrases:
phrase = phrase.strip().lower()
if phrase != "" and is_acceptable(phrase, min_char_length, max_words_length):
phrase_list.append(phrase)
phrase_list += extract_adjoined_candidates(sentence_list, stop_word_list, min_words_length_adj,
max_words_length_adj, min_phrase_freq_adj)
return phrase_list
def is_acceptable(phrase, min_char_length, max_words_length):
# a phrase must have a min length in characters
if len(phrase) < min_char_length:
return 0
# a phrase must have a max number of words
words = phrase.split()
if len(words) > max_words_length:
return 0
digits = 0
alpha = 0
for i in range(0, len(phrase)):
if phrase[i].isdigit():
digits += 1
elif phrase[i].isalpha():
alpha += 1
# a phrase must have at least one alpha character
if alpha == 0:
return 0
# a phrase must have more alpha than digits characters
if digits > alpha:
return 0
return 1
def calculate_word_scores(phraseList):
word_frequency = {}
word_degree = {}
for phrase in phraseList:
word_list = separate_words(phrase, 0)
word_list_length = len(word_list)
word_list_degree = word_list_length - 1
# if word_list_degree > 3: word_list_degree = 3 #exp.
for word in word_list:
word_frequency.setdefault(word, 0)
word_frequency[word] += 1
word_degree.setdefault(word, 0)
word_degree[word] += word_list_degree # orig.
# word_degree[word] += 1/(word_list_length*1.0) #exp.
for item in word_frequency:
word_degree[item] = word_degree[item] + word_frequency[item]
# Calculate Word scores = deg(w)/frew(w)
word_score = {}
for item in word_frequency:
word_score.setdefault(item, 0)
word_score[item] = word_degree[item] / (word_frequency[item] * 1.0) # orig.
# word_score[item] = word_frequency[item]/(word_degree[item] * 1.0) #exp.
return word_score
def generate_candidate_keyword_scores(phrase_list, word_score, min_keyword_frequency=1):
keyword_candidates = {}
for phrase in phrase_list:
if min_keyword_frequency > 1:
if phrase_list.count(phrase) < min_keyword_frequency:
continue
keyword_candidates.setdefault(phrase, 0)
word_list = separate_words(phrase, 0)
candidate_score = 0
for word in word_list:
candidate_score += word_score[word]
keyword_candidates[phrase] = candidate_score
return keyword_candidates
class Rake(object):
def __init__(self, stop_words_path, min_char_length=1, max_words_length=5, min_keyword_frequency=1,
min_words_length_adj=1, max_words_length_adj=1, min_phrase_freq_adj=2):
self.__stop_words_path = stop_words_path
self.__stop_words_list = load_stop_words(stop_words_path)
self.__min_char_length = min_char_length
self.__max_words_length = max_words_length
self.__min_keyword_frequency = min_keyword_frequency
self.__min_words_length_adj = min_words_length_adj
self.__max_words_length_adj = max_words_length_adj
self.__min_phrase_freq_adj = min_phrase_freq_adj
def run(self, text):
sentence_list = split_sentences(text)
stop_words_pattern = build_stop_word_regex(self.__stop_words_list)
phrase_list = generate_candidate_keywords(sentence_list, stop_words_pattern, self.__stop_words_list,
self.__min_char_length, self.__max_words_length,
self.__min_words_length_adj, self.__max_words_length_adj,
self.__min_phrase_freq_adj)
word_scores = calculate_word_scores(phrase_list)
keyword_candidates = generate_candidate_keyword_scores(phrase_list, word_scores, self.__min_keyword_frequency)
sorted_keywords = sorted(six.iteritems(keyword_candidates), key=operator.itemgetter(1), reverse=True)
return sorted_keywords
if test and __name__ == '__main__':
text = "Compatibility of systems of linear constraints over the set of natural numbers. Criteria of compatibility of a system of linear Diophantine equations, strict inequations, and nonstrict inequations are considered. Upper bounds for components of a minimal set of solutions and algorithms of construction of minimal generating sets of solutions for all types of systems are given. These criteria and the corresponding algorithms for constructing a minimal supporting set of solutions can be used in solving all the considered types of systems and systems of mixed types."
# Split text into sentences
sentenceList = split_sentences(text)
# stoppath = "FoxStoplist.txt" #Fox stoplist contains "numbers", so it will not find "natural numbers" like in Table 1.1
stoppath = "data/stoplists/SmartStoplist.txt" # SMART stoplist misses some of the lower-scoring keywords in Figure 1.5, which means that the top 1/3 cuts off one of the 4.0 score words in Table 1.1
stopwordpattern = build_stop_word_regex(stoppath)
# generate candidate keywords
phraseList = generate_candidate_keywords(sentenceList, stopwordpattern, load_stop_words(stoppath))
# calculate individual word scores
wordscores = calculate_word_scores(phraseList)
# generate candidate keyword scores
keywordcandidates = generate_candidate_keyword_scores(phraseList, wordscores)
if debug: print(keywordcandidates)
sortedKeywords = sorted(six.iteritems(keywordcandidates), key=operator.itemgetter(1), reverse=True)
if debug: print(sortedKeywords)
totalKeywords = len(sortedKeywords)
if debug: print(totalKeywords)
print(sortedKeywords[0:(totalKeywords // 3)])
rake = Rake("data/stoplists/SmartStoplist.txt")
keywords = rake.run(text)
print(keywords)