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queue.go
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queue.go
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// Copyright (c) HashiCorp, Inc.
// SPDX-License-Identifier: MPL-2.0
package memberlist
import (
"math"
"sync"
"github.com/google/btree"
)
// TransmitLimitedQueue is used to queue messages to broadcast to
// the cluster (via gossip) but limits the number of transmits per
// message. It also prioritizes messages with lower transmit counts
// (hence newer messages).
type TransmitLimitedQueue struct {
// NumNodes returns the number of nodes in the cluster. This is
// used to determine the retransmit count, which is calculated
// based on the log of this.
NumNodes func() int
// RetransmitMult is the multiplier used to determine the maximum
// number of retransmissions attempted.
RetransmitMult int
mu sync.Mutex
tq *btree.BTree // stores *limitedBroadcast as btree.Item
tm map[string]*limitedBroadcast
idGen int64
}
type limitedBroadcast struct {
transmits int // btree-key[0]: Number of transmissions attempted.
msgLen int64 // btree-key[1]: copied from len(b.Message())
id int64 // btree-key[2]: unique incrementing id stamped at submission time
b Broadcast
name string // set if Broadcast is a NamedBroadcast
}
// Less tests whether the current item is less than the given argument.
//
// This must provide a strict weak ordering.
// If !a.Less(b) && !b.Less(a), we treat this to mean a == b (i.e. we can only
// hold one of either a or b in the tree).
//
// default ordering is
// - [transmits=0, ..., transmits=inf]
// - [transmits=0:len=999, ..., transmits=0:len=2, ...]
// - [transmits=0:len=999,id=999, ..., transmits=0:len=999:id=1, ...]
func (b *limitedBroadcast) Less(than btree.Item) bool {
o := than.(*limitedBroadcast)
if b.transmits < o.transmits {
return true
} else if b.transmits > o.transmits {
return false
}
if b.msgLen > o.msgLen {
return true
} else if b.msgLen < o.msgLen {
return false
}
return b.id > o.id
}
// for testing; emits in transmit order if reverse=false
func (q *TransmitLimitedQueue) orderedView(reverse bool) []*limitedBroadcast {
q.mu.Lock()
defer q.mu.Unlock()
out := make([]*limitedBroadcast, 0, q.lenLocked())
q.walkReadOnlyLocked(reverse, func(cur *limitedBroadcast) bool {
out = append(out, cur)
return true
})
return out
}
// walkReadOnlyLocked calls f for each item in the queue traversing it in
// natural order (by Less) when reverse=false and the opposite when true. You
// must hold the mutex.
//
// This method panics if you attempt to mutate the item during traversal. The
// underlying btree should also not be mutated during traversal.
func (q *TransmitLimitedQueue) walkReadOnlyLocked(reverse bool, f func(*limitedBroadcast) bool) {
if q.lenLocked() == 0 {
return
}
iter := func(item btree.Item) bool {
cur := item.(*limitedBroadcast)
prevTransmits := cur.transmits
prevMsgLen := cur.msgLen
prevID := cur.id
keepGoing := f(cur)
if prevTransmits != cur.transmits || prevMsgLen != cur.msgLen || prevID != cur.id {
panic("edited queue while walking read only")
}
return keepGoing
}
if reverse {
q.tq.Descend(iter) // end with transmit 0
} else {
q.tq.Ascend(iter) // start with transmit 0
}
}
// Broadcast is something that can be broadcasted via gossip to
// the memberlist cluster.
type Broadcast interface {
// Invalidates checks if enqueuing the current broadcast
// invalidates a previous broadcast
Invalidates(b Broadcast) bool
// Returns a byte form of the message
Message() []byte
// Finished is invoked when the message will no longer
// be broadcast, either due to invalidation or to the
// transmit limit being reached
Finished()
}
// NamedBroadcast is an optional extension of the Broadcast interface that
// gives each message a unique string name, and that is used to optimize
//
// You shoud ensure that Invalidates() checks the same uniqueness as the
// example below:
//
// func (b *foo) Invalidates(other Broadcast) bool {
// nb, ok := other.(NamedBroadcast)
// if !ok {
// return false
// }
// return b.Name() == nb.Name()
// }
//
// Invalidates() isn't currently used for NamedBroadcasts, but that may change
// in the future.
type NamedBroadcast interface {
Broadcast
// The unique identity of this broadcast message.
Name() string
}
// UniqueBroadcast is an optional interface that indicates that each message is
// intrinsically unique and there is no need to scan the broadcast queue for
// duplicates.
//
// You should ensure that Invalidates() always returns false if implementing
// this interface. Invalidates() isn't currently used for UniqueBroadcasts, but
// that may change in the future.
type UniqueBroadcast interface {
Broadcast
// UniqueBroadcast is just a marker method for this interface.
UniqueBroadcast()
}
// QueueBroadcast is used to enqueue a broadcast
func (q *TransmitLimitedQueue) QueueBroadcast(b Broadcast) {
q.queueBroadcast(b, 0)
}
// lazyInit initializes internal data structures the first time they are
// needed. You must already hold the mutex.
func (q *TransmitLimitedQueue) lazyInit() {
if q.tq == nil {
q.tq = btree.New(32)
}
if q.tm == nil {
q.tm = make(map[string]*limitedBroadcast)
}
}
// queueBroadcast is like QueueBroadcast but you can use a nonzero value for
// the initial transmit tier assigned to the message. This is meant to be used
// for unit testing.
func (q *TransmitLimitedQueue) queueBroadcast(b Broadcast, initialTransmits int) {
q.mu.Lock()
defer q.mu.Unlock()
q.lazyInit()
if q.idGen == math.MaxInt64 {
// it's super duper unlikely to wrap around within the retransmit limit
q.idGen = 1
} else {
q.idGen++
}
id := q.idGen
lb := &limitedBroadcast{
transmits: initialTransmits,
msgLen: int64(len(b.Message())),
id: id,
b: b,
}
unique := false
if nb, ok := b.(NamedBroadcast); ok {
lb.name = nb.Name()
} else if _, ok := b.(UniqueBroadcast); ok {
unique = true
}
// Check if this message invalidates another.
if lb.name != "" {
if old, ok := q.tm[lb.name]; ok {
old.b.Finished()
q.deleteItem(old)
}
} else if !unique {
// Slow path, hopefully nothing hot hits this.
var remove []*limitedBroadcast
q.tq.Ascend(func(item btree.Item) bool {
cur := item.(*limitedBroadcast)
// Special Broadcasts can only invalidate each other.
switch cur.b.(type) {
case NamedBroadcast:
// noop
case UniqueBroadcast:
// noop
default:
if b.Invalidates(cur.b) {
cur.b.Finished()
remove = append(remove, cur)
}
}
return true
})
for _, cur := range remove {
q.deleteItem(cur)
}
}
// Append to the relevant queue.
q.addItem(lb)
}
// deleteItem removes the given item from the overall datastructure. You
// must already hold the mutex.
func (q *TransmitLimitedQueue) deleteItem(cur *limitedBroadcast) {
_ = q.tq.Delete(cur)
if cur.name != "" {
delete(q.tm, cur.name)
}
if q.tq.Len() == 0 {
// At idle there's no reason to let the id generator keep going
// indefinitely.
q.idGen = 0
}
}
// addItem adds the given item into the overall datastructure. You must already
// hold the mutex.
func (q *TransmitLimitedQueue) addItem(cur *limitedBroadcast) {
_ = q.tq.ReplaceOrInsert(cur)
if cur.name != "" {
q.tm[cur.name] = cur
}
}
// getTransmitRange returns a pair of min/max values for transmit values
// represented by the current queue contents. Both values represent actual
// transmit values on the interval [0, len). You must already hold the mutex.
func (q *TransmitLimitedQueue) getTransmitRange() (minTransmit, maxTransmit int) {
if q.lenLocked() == 0 {
return 0, 0
}
minItem, maxItem := q.tq.Min(), q.tq.Max()
if minItem == nil || maxItem == nil {
return 0, 0
}
min := minItem.(*limitedBroadcast).transmits
max := maxItem.(*limitedBroadcast).transmits
return min, max
}
// GetBroadcasts is used to get a number of broadcasts, up to a byte limit
// and applying a per-message overhead as provided.
func (q *TransmitLimitedQueue) GetBroadcasts(overhead, limit int) [][]byte {
q.mu.Lock()
defer q.mu.Unlock()
// Fast path the default case
if q.lenLocked() == 0 {
return nil
}
transmitLimit := retransmitLimit(q.RetransmitMult, q.NumNodes())
var (
bytesUsed int
toSend [][]byte
reinsert []*limitedBroadcast
)
// Visit fresher items first, but only look at stuff that will fit.
// We'll go tier by tier, grabbing the largest items first.
minTr, maxTr := q.getTransmitRange()
for transmits := minTr; transmits <= maxTr; /*do not advance automatically*/ {
free := int64(limit - bytesUsed - overhead)
if free <= 0 {
break // bail out early
}
// Search for the least element on a given tier (by transmit count) as
// defined in the limitedBroadcast.Less function that will fit into our
// remaining space.
greaterOrEqual := &limitedBroadcast{
transmits: transmits,
msgLen: free,
id: math.MaxInt64,
}
lessThan := &limitedBroadcast{
transmits: transmits + 1,
msgLen: math.MaxInt64,
id: math.MaxInt64,
}
var keep *limitedBroadcast
q.tq.AscendRange(greaterOrEqual, lessThan, func(item btree.Item) bool {
cur := item.(*limitedBroadcast)
// Check if this is within our limits
if int64(len(cur.b.Message())) > free {
// If this happens it's a bug in the datastructure or
// surrounding use doing something like having len(Message())
// change over time. There's enough going on here that it's
// probably sane to just skip it and move on for now.
return true
}
keep = cur
return false
})
if keep == nil {
// No more items of an appropriate size in the tier.
transmits++
continue
}
msg := keep.b.Message()
// Add to slice to send
bytesUsed += overhead + len(msg)
toSend = append(toSend, msg)
// Check if we should stop transmission
q.deleteItem(keep)
if keep.transmits+1 >= transmitLimit {
keep.b.Finished()
} else {
// We need to bump this item down to another transmit tier, but
// because it would be in the same direction that we're walking the
// tiers, we will have to delay the reinsertion until we are
// finished our search. Otherwise we'll possibly re-add the message
// when we ascend to the next tier.
keep.transmits++
reinsert = append(reinsert, keep)
}
}
for _, cur := range reinsert {
q.addItem(cur)
}
return toSend
}
// NumQueued returns the number of queued messages
func (q *TransmitLimitedQueue) NumQueued() int {
q.mu.Lock()
defer q.mu.Unlock()
return q.lenLocked()
}
// lenLocked returns the length of the overall queue datastructure. You must
// hold the mutex.
func (q *TransmitLimitedQueue) lenLocked() int {
if q.tq == nil {
return 0
}
return q.tq.Len()
}
// Reset clears all the queued messages. Should only be used for tests.
func (q *TransmitLimitedQueue) Reset() {
q.mu.Lock()
defer q.mu.Unlock()
q.walkReadOnlyLocked(false, func(cur *limitedBroadcast) bool {
cur.b.Finished()
return true
})
q.tq = nil
q.tm = nil
q.idGen = 0
}
// Prune will retain the maxRetain latest messages, and the rest
// will be discarded. This can be used to prevent unbounded queue sizes
func (q *TransmitLimitedQueue) Prune(maxRetain int) {
q.mu.Lock()
defer q.mu.Unlock()
// Do nothing if queue size is less than the limit
for q.tq.Len() > maxRetain {
item := q.tq.Max()
if item == nil {
break
}
cur := item.(*limitedBroadcast)
cur.b.Finished()
q.deleteItem(cur)
}
}