Day2Loops&IC-checkpoint.ipynb

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 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Words"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "words = ['play', 'filling', 'bar', 'theatre', 'easygoing', 'date', 'lead', 'that', 'story',  'island']"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**Print every word in upper case**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "PLAY\n",
      "FILLING\n",
      "BAR\n",
      "THEATRE\n",
      "EASYGOING\n",
      "DATE\n",
      "LEAD\n",
      "THAT\n",
      "STORY\n",
      "ISLAND\n"
     ]
    }
   ],
   "source": [
    "words = ['play', 'filling', 'bar', 'theatre', 'easygoing', 'date', 'lead', 'that', 'story', 'island']\n",
    "\n",
    "for word in words:\n",
    "    upper_word = \"\"\n",
    "    for char in word:\n",
    "        \n",
    "        if 'a' <= char <= 'z':\n",
    "            upper_word += chr(ord(char) - 32)\n",
    "        else:\n",
    "            upper_word += char\n",
    "    print(upper_word)\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**Create a new list containing only words with 5 or more letters**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "['filling', 'theatre', 'easygoing', 'story', 'island']\n"
     ]
    }
   ],
   "source": [
    "words = ['play', 'filling', 'bar', 'theatre', 'easygoing', 'date', 'lead', 'that', 'story', 'island']\n",
    "\n",
    "def calculate_length(word):\n",
    "    length = 0\n",
    "    for _ in word:\n",
    "        length += 1\n",
    "    return length\n",
    "\n",
    "long_words = []\n",
    "for word in words:\n",
    "    if calculate_length(word) >= 5:\n",
    "        long_words.append(word)\n",
    "\n",
    "print(long_words)\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**Print the first word starting with \"t\"**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "theatre\n"
     ]
    }
   ],
   "source": [
    "words = ['play', 'filling', 'bar', 'theatre', 'easygoing', 'date', 'lead', 'that', 'story', 'island']\n",
    "\n",
    "for word in words:\n",
    "    if len(word) > 0 and word[0] == 't':\n",
    "        print(word)\n",
    "        break \n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Numbers"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**Create a list containing the square of every number from 1 to 10**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 4, 9, 16, 25, 36, 49, 64, 81, 100]\n"
     ]
    }
   ],
   "source": [
    "squares = []\n",
    "\n",
    "for number in range(1, 11):  # Manually simulate a range from 1 to 10\n",
    "    square = number * number\n",
    "    squares.append(square)\n",
    "\n",
    "print(squares)\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**Print a list containing the square of every odd number from 1 to 10**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 9, 25, 49, 81]\n"
     ]
    }
   ],
   "source": [
    "odd_squares = []\n",
    "\n",
    "for number in range(1, 11):\n",
    "    if number % 2 != 0: \n",
    "        square = number * number\n",
    "        odd_squares.append(square)\n",
    "\n",
    "print(odd_squares)\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**Create a list with the squares of all multiples of 8 below 1000**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[64, 256, 576, 1024, 1600, 2304, 3136, 4096, 5184, 6400, 7744, 9216, 10816, 12544, 14400, 16384, 18496, 20736, 23104, 25600, 28224, 30976, 33856, 36864, 40000, 43264, 46656, 50176, 53824, 57600, 61504, 65536, 69696, 73984, 78400, 82944, 87616, 92416, 97344, 102400, 107584, 112896, 118336, 123904, 129600, 135424, 141376, 147456, 153664, 160000, 166464, 173056, 179776, 186624, 193600, 200704, 207936, 215296, 222784, 230400, 238144, 246016, 254016, 262144, 270400, 278784, 287296, 295936, 304704, 313600, 322624, 331776, 341056, 350464, 360000, 369664, 379456, 389376, 399424, 409600, 419904, 430336, 440896, 451584, 462400, 473344, 484416, 495616, 506944, 518400, 529984, 541696, 553536, 565504, 577600, 589824, 602176, 614656, 627264, 640000, 652864, 665856, 678976, 692224, 705600, 719104, 732736, 746496, 760384, 774400, 788544, 802816, 817216, 831744, 846400, 861184, 876096, 891136, 906304, 921600, 937024, 952576, 968256, 984064]\n"
     ]
    }
   ],
   "source": [
    "multiples_of_8_squares = []\n",
    "\n",
    "for number in range(1, 1000): \n",
    "    if number % 8 == 0: \n",
    "        square = number * number\n",
    "        multiples_of_8_squares.append(square)\n",
    "\n",
    "print(multiples_of_8_squares)\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## People"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "people = [\n",
    "    {\n",
    "        \"name\": \"Juan\",\n",
    "        \"age\": 34,\n",
    "        \"n_kids\": 2\n",
    "    },\n",
    "    {\n",
    "        \"name\": \"Pepe\",\n",
    "        \"age\": 27,\n",
    "        \"n_kids\": 0\n",
    "    },\n",
    "    {\n",
    "        \"name\": \"Sonia\",\n",
    "        \"age\": 41,\n",
    "        \"n_kids\": 1\n",
    "    },\n",
    "    {\n",
    "        \"name\": \"Lucía\",\n",
    "        \"age\": 22,\n",
    "        \"n_kids\": 2\n",
    "    },\n",
    "    {\n",
    "        \"name\": \"Leo\",\n",
    "        \"age\": 55,\n",
    "        \"n_kids\": 5\n",
    "    }\n",
    "]"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**How many people are there?**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "5\n"
     ]
    }
   ],
   "source": [
    "people = [\n",
    "    {\"name\": \"Juan\", \"age\": 34, \"n_kids\": 2},\n",
    "    {\"name\": \"Pepe\", \"age\": 27, \"n_kids\": 0},\n",
    "    {\"name\": \"Sonia\", \"age\": 41, \"n_kids\": 1},\n",
    "    {\"name\": \"Lucía\", \"age\": 22, \"n_kids\": 2},\n",
    "    {\"name\": \"Leo\", \"age\": 55, \"n_kids\": 5}\n",
    "]\n",
    "\n",
    "total_people = len(people)\n",
    "\n",
    "print(total_people)\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**How many people have kids**?"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 10,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "4\n"
     ]
    }
   ],
   "source": [
    "people_with_kids = sum(1 for person in people if person[\"n_kids\"] > 0)\n",
    "\n",
    "print(people_with_kids)\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**How many kids do they have in total?**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 11,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "10\n"
     ]
    }
   ],
   "source": [
    "total_kids = sum(person[\"n_kids\"] for person in people)\n",
    "\n",
    "print(total_kids)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**In a year's time, names ending with \"a\" will have an extra kid. Create a list of dictionaries with people's info in a year's time**"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 12,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[{'name': 'Juan', 'age': 34, 'n_kids': 2}, {'name': 'Pepe', 'age': 27, 'n_kids': 0}, {'name': 'Sonia', 'age': 41, 'n_kids': 2}, {'name': 'Lucía', 'age': 22, 'n_kids': 3}, {'name': 'Leo', 'age': 55, 'n_kids': 5}]\n"
     ]
    }
   ],
   "source": [
    "updated_people = [\n",
    "    {**person, \"n_kids\": person[\"n_kids\"] + 1} if person[\"name\"].endswith(\"a\") else person\n",
    "    for person in people\n",
    "]\n",
    "\n",
    "print(updated_people)\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
  }
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