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Since C++23, call operators can be declared static, which may lead to better generated code. Also, a lambda's operator() will also be declared static if it does not capture anything.
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Since C++23, call operators can be declared
static
, which may lead to better generated code. Also, a lambda'soperator()
will also be declaredstatic
if it does not capture anything.The text was updated successfully, but these errors were encountered: