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Merge pull request #127 from ikostan/exercism-sync/3f7821b20107417c
[Sync Iteration] python/perfect-numbers/1
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"""
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Determine if a number is perfect, abundant, or deficient based on
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Nicomachus' (60 - 120 CE) classification scheme for positive integers.
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"""
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def classify(number: int) -> str:
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"""
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A perfect number equals the sum of its positive divisors.
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:param number: int a positive integer
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:return: str the classification of the input integer
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"""
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if number < 1:
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raise ValueError(
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"Classification is only possible for positive integers."
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)
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total_divisors: int = sum(i for i in range(1, number) if number % i == 0)
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if total_divisors == number:
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return "perfect"
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if number < total_divisors:
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return "abundant"
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return "deficient"

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