Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama"
is a palindrome.
"race a car"
is not a palindrome.
Note:
-
Have you consider that the string might be empty? This is a good question to ask during an interview.
-
For the purpose of this problem, we define empty string as valid palindrome.
直接前后比较即可
class Solution {
public:
bool isPalindrome(string s) {
int n = s.size();
if (n == 0)
return true;
int left = next(s, -1);
int right = prev(s, n);
for (int i = next(s, -1), j = prev(s, n); i < j; i = next(s, i), j = prev(s, j)) {
if (!equals(s[i], s[j]))
return false;
}
return true;
}
private:
int next(const string &s, int i) {
i++;
while (!isalnum(s[i])) i++;
return i;
}
int prev(const string &s, int j) {
j--;
while (!isalnum(s[j])) j--;
return j;
}
bool equals(char a, char b) {
a = tolower(a);
b = tolower(b);
return a == b;
}
};