The Employee
table holds all employees including their managers. Every employee has an Id
, and there is also a column for the manager Id
.
+----+-------+--------+-----------+
| Id | Name | Salary | ManagerId |
+----+-------+--------+-----------+
| 1 | Joe | 70000 | 3 |
| 2 | Henry | 80000 | 4 |
| 3 | Sam | 60000 | NULL |
| 4 | Max | 90000 | NULL |
+----+-------+--------+-----------+
Given the Employee
table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
+----------+
| Employee |
+----------+
| Joe |
+----------+
select e1.Name as Employee from Employee2 as e1
where e1.ManagerId is not NULL
and e1.Salary > (select Salary from Employee2 where Id=e1.ManagerId);
结果超时,原因是相关子查询效率非常低,应该尽量避免
select e1.Name as Employee from Employee2 as e1
join Employee2 as e2
on e1.ManagerId = e2.Id and e1.Salary > e2.Salary
where e1.ManagerId is not NULL;
结果顺利通过。