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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Sulphuric Acid</title>
<script src="chem1.js" defer></script>
<script src="timer.js" defer></script>
<meta name="Keywords" content="exercises, balancing, chemistry, equations, hydrogen-chloride, ammonia, nitric-acid, nitrates, sulphur-dioxide, hydrogen-sulphide, sodium-hydroxide, sulphuric-acid, preparation ">
<meta name="author" content="Jiban Majumdar">
<link rel="stylesheet" href="mystyle.css">
</head>
<body>
<div>
<img src="myPhoto.jpg" alt="webmaster" width="150" height="200"> <br> <a href="mailto:jibanmajumdar@gmail.com">webmaster</a>
</div>
<table class="center">
<tr>
<td><a href="index.html">Home Page</a></td>
<td><a href="equ.html">Elementary Equations</a></td>
<td><a href="advanced.html">Advanced Equations</a></td>
<td><a href="assorted.html">Assorted Equations</a></td>
<td><a href="hydrogen-chloride.html">Hydrogen Chloride</a></td>
<td><a href="chlorine.html">Chlorine</a></td>
</tr>
<tr>
<td><a href="ammonia.html">Ammonia</a></td>
<td><a href="sulphur-dioxide.html">Sulphur Dioxide</a></td>
<td><a href="hydrogen-sulphide.html">Hydrogen Sulphide</a></td>
<td><a href="nitric-acid.html">Nitric Acid</a></td>
<td><a href="sodium-hydroxide.html">Sodium Hydroxide</a></td>
<td></td>
</tr>
</table>
<h1 style="text-align:center;">Sulphuric Acid</h1>
<h2>Practise balancing equations: </h2><h3>Direction:</h3> <ul><li>In the following equations you will see a blank box before the symbol of each compound and element. Enter the lowest possible number in each box, or leave the box blank if you think the chemical needn't have a number (i.e. the number is equivalent to '1').</li>
<li>When you think the equation is balanced, click on the small button <span style= "color:blue;"><b>"Check answer"</b></span> that appears below it.</li> <lI>If your equation is incorrect, then click the button <span style= "color:blue;"><b> "Reset"</b></span> and try balancing the equation again.</li> <li>In case you are in a hurry or are unable to balance, then click the button <span style= "color:blue;"><b>"Show answer."</b></span></li>
<li>If you want to know the time taken (minutes:seconds) to balance a chemical equation, you click the <span style="color:blue;"><b>"Start"</b></span> button and after balancing the equation, click the <span style="color:blue;"><b>"Stop"</b></span>button. Once, you have noted the time, click the <span style="color:blue;"><b>"Reset Timer"</b></span> button.
</li>
</ul>
<h3>Note:</h3> If you get no response after clicking 'Check answer' or 'Show answer', your browser has disabled to run this
program. Enable it by clicking below the 'address
bar' and follow the instructions.
<form name="equations">
<h4>Manufacture of Sulphuric Acid (Contact Process) </h4>
<ul><li>In the first step, Sulphur is burnt in air to form Sulphur dioxide gas:</li></ul>
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q1a>S + <input style="font-size: 16px; text-align: center" size=1 name=q1b>O<sub>2</sub> →<input style="font-size: 16px; text-align: center" size=1 name=q1c>SO<sub>2</sub> </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(1,'Manufacture of Sulphuric Acid',1,1,1,0,0,0,'S + O<sub>2</sub>','SO<sub>2</sub> ');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(1,'Manufacture of Sulphuric Acid',1,1,1,0,0,0,'S + O<sub>2</sub>','SO<sub>2</sub> ');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer1">00:00</span>
<button type="button" onclick="startTimer('timer1')">Start</button>
<button type="button" onclick="stopTimer('timer1')">Stop</button>
<button type="button" onclick="resetTimer('timer1')">Reset Timer</button>
</p>
<p></p>
<ul><li>In the next step, Sulphur dioxide is mixed with air and passed over hot Vanadium Pentoxide catalyst at 450<sup>o</sup>C and 1 atmosphere pressure to form Sulphur trioxide:</li></ul>
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q2a>SO<sub>2</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q2b>O<sub>2</sub> ⇌ <input style="font-size: 16px; text-align: center;" size=1 name=q2c>SO<sub>3</sub> </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(2,'Manufacture of Sulphuric Acid',2,1,2,0,0,0,'SO<sub>2</sub> + O<sub>2</sub>','SO<sub>3</sub> ');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(2,'Manufacture of Sulphuric Acid',2,1,2,0,0,0,'2SO<sub>2</sub> + O<sub>2</sub>','2SO<sub>3</sub> ');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer2">00:00</span>
<button type="button" onclick="startTimer('timer2')">Start</button>
<button type="button" onclick="stopTimer('timer2')">Stop</button>
<button type="button" onclick="resetTimer('timer2')">Reset Timer</button>
</p>
<p></p>
<ul><li>In the next step, Sulphur trioxide is absorbed in concentrated Sulphuric acid to form Oleum (H<sub>2</sub>S<sub>2</sub>O<sub>7</sub>):</li></ul>
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q3a>SO<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q3b>H<sub>2</sub>SO<sub>4</sub>→<input style="font-size: 16px; text-align: center;" size=1 name=q3c>H<sub>2</sub>S<sub>2</sub>O<sub>7</sub> </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(3,'Manufacture of Sulphuric Acid',1,1,1,0,0,0,'SO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','H<sub>2</sub>S<sub>2</sub>O<sub>7</sub>');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(3,'Manufacture of Sulphuric Acid',1,1,1,0,0,0,'SO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','H<sub>2</sub>S<sub>2</sub>O<sub>7</sub>');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer3">00:00</span>
<button type="button" onclick="startTimer('timer3')">Start</button>
<button type="button" onclick="stopTimer('timer3')">Stop</button>
<button type="button" onclick="resetTimer('timer3')">Reset Timer</button>
</p>
<p></p>
<ul><li>In the final step,water is added to Oleum to form concentrated Sulphuric acid:</li></ul>
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q4a>H<sub>2</sub>S<sub>2</sub>O<sub>7</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q4b>H<sub>2</sub>O→<input style="font-size: 16px; text-align: center;" size=1 name=q4c>H<sub>2</sub>SO<sub>4</sub> </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(4,'Manufacture of Sulphuric Acid',1,1,2,0,0,0,'H<sub>2</sub>S<sub>2</sub>O<sub>7</sub> + H<sub>2</sub>O','H<sub>2</sub>SO<sub>4</sub>');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(4,'Manufacture of Sulphuric Acid',1,1,2,0,0,0,'H<sub>2</sub>S<sub>2</sub>O<sub>7</sub> + H<sub>2</sub>O','2H<sub>2</sub>SO<sub>4</sub>');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer4">00:00</span>
<button type="button" onclick="startTimer('timer4')">Start</button>
<button type="button" onclick="stopTimer('timer4')">Stop</button>
<button type="button" onclick="resetTimer('timer4')">Reset Timer</button>
</p>
<p></p>
<h4>Reactions of dilute Sulphuric Acid (As an acid):</h4>
1.When Magnesium metal is added to dilute Sulphuric acid, bubbles of Hydrogen gas are liberated:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q5a>Mg + <input style="font-size: 16px; text-align: center" size=1 name=q5b>H<sub>2</sub>SO<sub>4</sub> →<input
style="font-size: 16px; text-align: center;" size=1 name=q5c>MgSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q5d>H<sub>2</sub> </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(5,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'Mg + H<sub>2</sub>SO<sub>4</sub>','MgSO<sub>4</sub> + H<sub>2</sub>');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(5,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'Mg + H<sub>2</sub>SO<sub>4</sub>','MgSO<sub>4</sub> + H<sub>2</sub>');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer5">00:00</span>
<button type="button" onclick="startTimer('timer5')">Start</button>
<button type="button" onclick="stopTimer('timer5')">Stop</button>
<button type="button" onclick="resetTimer('timer5')">Reset Timer</button>
</p>
<p></p>
2.When Zinc metal is added to dilute Sulphuric acid, bubbles of Hydrogen gas are liberated:
<p>
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q6a>Zn + <input style="font-size: 16px; text-align: center" size=1 name=q6b>H<sub>2</sub>SO<sub>4</sub> →<input
style="font-size: 16px; text-align: center;" size=1 name=q6c>ZnSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q6d>H<sub>2</sub> </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(6,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'Zn + H<sub>2</sub>SO<sub>4</sub>','ZnSO<sub>4</sub> + H<sub>2</sub>');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(6,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'Zn + H<sub>2</sub>SO<sub>4</sub>','ZnSO<sub>4</sub> + H<sub>2</sub>');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer6">00:00</span>
<button type="button" onclick="startTimer('timer6')">Start</button>
<button type="button" onclick="stopTimer('timer6')">Stop</button>
<button type="button" onclick="resetTimer('timer6')">Reset Timer</button>
</p>
<p></p>
3.When Iron metal is added to dilute Sulphuric acid, bubbles of Hydrogen gas are liberated:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q7a>Fe + <input style="font-size: 16px; text-align: center" size=1 name=q7b>H<sub>2</sub>SO<sub>4</sub> →<input
style="font-size: 16px; text-align: center;" size=1 name=q7c>FeSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q7d>H<sub>2</sub> </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(7,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'Fe + H<sub>2</sub>SO<sub>4</sub>','FeSO<sub>4</sub> + H<sub>2</sub>');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(7,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'Fe + H<sub>2</sub>SO<sub>4</sub>','FeSO<sub>4</sub> + H<sub>2</sub>');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer7">00:00</span>
<button type="button" onclick="startTimer('timer7')">Start</button>
<button type="button" onclick="stopTimer('timer7')">Stop</button>
<button type="button" onclick="resetTimer('timer7')">Reset Timer</button>
</p>
<p></p>
4.Magnesium oxide reacts with dilute Sulphuric acid to form Magnesium sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q8a>MgO + <input style="font-size: 16px; text-align: center;" size=1 name=q8b>H<sub>2</sub>SO<sub>4</sub> →<input
style="font-size: 16px; text-align: center;" size=1 name=q8c>MgSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q8d>H<sub>2</sub>O </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(8,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'MgO + H<sub>2</sub>SO<sub>4</sub>','MgSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(7,'Reactions of Sulphuric acid (As an acid)',1,2,1,1,0,0,'MgO + H<sub>2</sub>SO<sub>4</sub>','MgSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer8">00:00</span>
<button type="button" onclick="startTimer('timer8')">Start</button>
<button type="button" onclick="stopTimer('timer8')">Stop</button>
<button type="button" onclick="resetTimer('timer8')">Reset Timer</button>
</p>
<p></p>
5.Aluminium oxide reacts with dilute Sulphuric acid to form Aluminium sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q9a>Al<sub>2</sub>O<sub>3</sub> + <input style="font-size: 16px; text-align: center" size=1 name=q9b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center" size=1 name=q9c>Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q9d>H<sub>2</sub>O </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(9,'Reactions of Sulphuric Acid (As an acid)',1,3,1,3,0,0,'Al<sub>2</sub>O<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(9,'Reactions of Sulphuric Acid (As an acid)',1,3,1,3,0,0,'Al<sub>2</sub>O<sub>3</sub> + 3H<sub>2</sub>SO<sub>4</sub>','Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + 3H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer9">00:00</span>
<button type="button" onclick="startTimer('timer9')">Start</button>
<button type="button" onclick="stopTimer('timer9')">Stop</button>
<button type="button" onclick="resetTimer('timer9')">Reset Timer</button>
</p>
<p></p>
6.Zinc oxide reacts with dilute Sulphuric acid to form Zinc sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q10a>ZnO + <input style="font-size: 16px; text-align: center;" size=1 name=q10b>H<sub>2</sub>SO<sub>4</sub> →<input
style="font-size: 16px; text-align: center;" size=1 name=q10c>ZnSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q10d>H<sub>2</sub>O </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(10,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'ZnO + H<sub>2</sub>SO<sub>4</sub>','ZnSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(9,'Reactions of Sulphuric acid (As an acid)',1,2,1,1,0,0,'ZnO + H<sub>2</sub>SO<sub>4</sub>','ZnSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer10">00:00</span>
<button type="button" onclick="startTimer('timer10')">Start</button>
<button type="button" onclick="stopTimer('timer10')">Stop</button>
<button type="button" onclick="resetTimer('timer10')">Reset Timer</button>
</p>
<p></p>
7.Iron (III) oxide reacts with dilute Sulphuric acid to form Iron (III) sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q11a>Fe<sub>2</sub>O<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q11b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q11c>Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q11d>H<sub>2</sub>O </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(11,'Reactions of Sulphuric Acid (As an acid)',1,3,1,3,0,0,'Fe<sub>2</sub>O<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(11,'Reactions of Sulphuric acid (As an acid)',1,3,1,3,0,0,'Fe<sub>2</sub>O<sub>3</sub> + 3H<sub>2</sub>SO<sub>4</sub>','Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + 3H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer11">00:00</span>
<button type="button" onclick="startTimer('timer11')">Start</button>
<button type="button" onclick="stopTimer('timer11')">Stop</button>
<button type="button" onclick="resetTimer('timer11')">Reset Timer</button>
</p>
<p></p>
8.Copper (II) oxide reacts with dilute Sulphuric acid to form Copper (II) sulphate and water:
<p>
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q12a>CuO + <input style="font-size: 16px; text-align: center;" size=1 name=q12b>H<sub>2</sub>SO<sub>4</sub> →<input
style="font-size: 16px; text-align: center;" size=1 name=q12c>CuSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q12d>H<sub>2</sub>O </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(12,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,0,0,'CuO + H<sub>2</sub>SO<sub>4</sub>','CuSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(12,'Reactions of Sulphuric acid (As an acid)',1,1,1,1,0,0,'CuO + H<sub>2</sub>SO<sub>4</sub>','CuSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer12">00:00</span>
<button type="button" onclick="startTimer('timer12')">Start</button>
<button type="button" onclick="stopTimer('timer12')">Stop</button>
<button type="button" onclick="resetTimer('timer12')">Reset Timer</button>
</p>
<p></p>
9.Ammonia gas reacts with dilute Sulphuric acid to form Ammonium sulphate:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q13a>NH<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q13b>H<sub>2</sub>SO<sub>4</sub> →<input
style="font-size: 16px; text-align: center;" size=1 name=q13c>(NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub> </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(13,'Reactions of Sulphuric Acid (As an acid)',2,1,1,0,0,0,'NH<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','(NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub>');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(13,'Reactions of Sulphuric Acid (As an acid)',2,1,1,0,0,0,'2NH<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','(NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub>');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer13">00:00</span>
<button type="button" onclick="startTimer('timer13')">Start</button>
<button type="button" onclick="stopTimer('timer13')">Stop</button>
<button type="button" onclick="resetTimer('timer13')">Reset Timer</button>
</p>
<p></p>
10.dilute Sulphuric acid reacts with Potassium hydroxide to form Potassium sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q14a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q14b>KOH →<input style="font-size: 16px; text-align: center;" size=1 name=q14c>K<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center" size=1 name=q14d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(14,'Reactions of Sulphuric Acid (As an acid)',1,2,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + KOH','K<sub>2</sub>SO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(14,'Reactions of Sulphuric Acid (As an acid)',1,2,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + 2KOH','K<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer14">00:00</span>
<button type="button" onclick="startTimer('timer14')">Start</button>
<button type="button" onclick="stopTimer('timer14')">Stop</button>
<button type="button" onclick="resetTimer('timer14')">Reset Timer</button>
</p>
<p></p>
11.dilute Sulphuric acid reacts with Sodium hydroxide to form Sodium sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q15a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q15b>NaOH →<input style="font-size: 16px; text-align: center;" size=1 name=q15c>Na<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center" size=1 name=q15d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(15,'Reactions of Sulphuric Acid (As an acid)',1,2,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + NaOH','Na<sub>2</sub>SO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(15,'Reactions of Sulphuric Acid (As an acid)',1,2,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + 2NaOH','Na<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer15">00:00</span>
<button type="button" onclick="startTimer('timer15')">Start</button>
<button type="button" onclick="stopTimer('timer15')">Stop</button>
<button type="button" onclick="resetTimer('timer15')">Reset Timer</button>
</p>
<p></p>
12.dilute Sulphuric acid reacts with Calcium hydroxide to form Calcium sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q16a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q16b>Ca(OH)<sub>2</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q16c>CaSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q16d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(16,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Ca(OH)<sub>2</sub>','CaSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(16,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Ca(OH)<sub>2</sub>','CaSO<sub>4</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer16">00:00</span>
<button type="button" onclick="startTimer('timer16')">Start</button>
<button type="button" onclick="stopTimer('timer16')">Stop</button>
<button type="button" onclick="resetTimer('timer16')">Reset Timer</button>
</p>
<p></p>
13.dilute Sulphuric acid reacts with white Magnesium hydroxide to form colourless Magnesium sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q17a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q17b>Mg(OH)<sub>2</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q17c>MgSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q17d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(17,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Mg(OH)<sub>2</sub>','MgSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(17,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Mg(OH)<sub>2</sub>','MgSO<sub>4</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer17">00:00</span>
<button type="button" onclick="startTimer('timer17')">Start</button>
<button type="button" onclick="stopTimer('timer17')">Stop</button>
<button type="button" onclick="resetTimer('timer17')">Reset Timer</button>
</p>
<p></p>
14.dilute Sulphuric acid reacts with white Aluminium hydroxide to form colourless Aluminium sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q18a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q18b>Al(OH)<sub>3</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q18c>Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q18d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(18,'Reactions of Sulphuric Acid (As an acid)',3,2,1,6,0,0,'H<sub>2</sub>SO<sub>4</sub> + Al(OH)<sub>3</sub>','Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(18,'Reactions of Sulphuric Acid (As an acid)',3,2,1,6,0,0,'3H<sub>2</sub>SO<sub>4</sub> + 2Al(OH)<sub>3</sub>','Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + 6H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer18">00:00</span>
<button type="button" onclick="startTimer('timer18')">Start</button>
<button type="button" onclick="stopTimer('timer18')">Stop</button>
<button type="button" onclick="resetTimer('timer18')">Reset Timer</button>
</p>
<p></p>
15.dilute Sulphuric acid reacts with white Zinc hydroxide to form colourless Zinc sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q19a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q19b>Zn(OH)<sub>2</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q19c>ZnSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q19d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(19,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Zn(OH)<sub>2</sub>','ZnSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(19,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Zn(OH)<sub>2</sub>','ZnSO<sub>4</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer19">00:00</span>
<button type="button" onclick="startTimer('timer19')">Start</button>
<button type="button" onclick="stopTimer('timer19')">Stop</button>
<button type="button" onclick="resetTimer('timer19')">Reset Timer</button>
</p>
<p></p>
16.dilute Sulphuric acid reacts with green Iron(II) hydroxide to form light green Iron(II) sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q20a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q20b>Fe(OH)<sub>2</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q20c>FeSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q20d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(20,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Fe(OH)<sub>2</sub>','FeSO<sub>4</sub>) + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(20,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Fe(OH)<sub>2</sub>','FeSO<sub>4</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer20">00:00</span>
<button type="button" onclick="startTimer('timer20')">Start</button>
<button type="button" onclick="stopTimer('timer20')">Stop</button>
<button type="button" onclick="resetTimer('timer20')">Reset Timer</button>
</p>
<p></p>
17.dilute Sulphuric acid reacts with reddish brown Iron(III)hydroxide to form yellow Iron(III) sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q21a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q21b>Fe(OH)<sub>3</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q21c>
Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q21d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(21,'Reactions of Sulphuric Acid (As an acid)',3,2,1,6,0,0,'H<sub>2</sub>SO<sub>4</sub> + Fe(OH)<sub>3</sub>','Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(21,'Reactions of Sulphuric Acid (As an acid)',3,2,1,6,0,0,'3H<sub>2</sub>SO<sub>4</sub> + 2Fe(OH)<sub>3</sub>','Fe<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> + 6H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer21">00:00</span>
<button type="button" onclick="startTimer('timer21')">Start</button>
<button type="button" onclick="stopTimer('timer21')">Stop</button>
<button type="button" onclick="resetTimer('timer21')">Reset Timer</button>
</p>
<p></p>
18.dilute Sulphuric acid reacts with blue copper(II) hydroxide to form blue copper(II)sulphate and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;"
size=1 name=q22a>H<sub>2</sub>SO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q22b>Cu(OH)<sub>2</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q22c>CuSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q22d>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(22,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Cu(OH)<sub>2</sub>','CuSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" VALUE="Reset"> <input onclick="show(22,'Reactions of Sulphuric Acid (As an acid)',1,1,1,2,0,0,'H<sub>2</sub>SO<sub>4</sub> + Cu(OH)<sub>2</sub>','CuSO<sub>4</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer22">00:00</span>
<button type="button" onclick="startTimer('timer22')">Start</button>
<button type="button" onclick="stopTimer('timer22')">Stop</button>
<button type="button" onclick="resetTimer('timer22')">Reset Timer</button>
</p>
<p></p>
19.Potassium carbonate reacts with dilute Sulphuric acid to form Potassium sulphate, carbon dioxide and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q23a>K<sub>2</sub>CO<sub>3</sub>+<input style="font-size: 16px; text-align: center" size=1 name=q23b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center" size=1 name=q23c>K<sub>2</sub>SO<sub>4</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q23d>CO<sub>2</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q23e>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(23,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,1,0,'K<sub>2</sub>CO<sub>3</sub>+ H<sub>2</sub>SO<sub>4</sub>','K<sub>2</sub>SO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(23,'Reactions of Sulphuric acid (As an acid)',1,1,1,1,1,0,'K<sub>2</sub>CO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','K<sub>2</sub>SO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer23">00:00</span>
<button type="button" onclick="startTimer('timer23')">Start</button>
<button type="button" onclick="stopTimer('timer23')">Stop</button>
<button type="button" onclick="resetTimer('timer23')">Reset Timer</button>
</p>
<p></p>
20.Sodium carbonate reacts with dilute Sulphuric acid to form Sodium sulphate, carbon dioxide and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center" size=1 name=q24a>Na<sub>2</sub>CO<sub>3</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q24b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q24c>Na<sub>2</sub>SO<sub>4</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q24d>CO<sub>2</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q24e>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(24,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,1,0,'Na<sub>2</sub>CO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','Na<sub>2</sub>SO<sub>4</sub>+ CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(24,'Reactions of Sulphuric acid (As an acid)',1,1,1,1,1,0,'Na<sub>2</sub>CO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','Na<sub>2</sub>SO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
<p style="font-size:115%; text-align:center;">
<span style="color:blue;"><b>Time Taken:</b></span><span class="timer" id="timer24">00:00</span>
<button type="button" onclick="startTimer('timer24')">Start</button>
<button type="button" onclick="stopTimer('timer24')">Stop</button>
<button type="button" onclick="resetTimer('timer24')">Reset Timer</button>
</p>
<p></p>
21.Calcium carbonate reacts with dilute Sulphuric acid to form Calcium sulphate, carbon dioxide and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q25a>CaCO<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q25b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center" size=1 name=q25c>CaSO<sub>4</sub>+ <input style="font-size: 16px; text-align: center;" size=1 name=q25d>CO<sub>2</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q25e>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(25,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,1,0,'CaCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','CaSO<sub>4</sub>+ CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(25,'Reactions of Sulphuric acid (As an acid)',1,1,1,1,1,0,'CaCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','CaSO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
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22.Magnesium carbonate reacts with dilute Sulphuric acid to form Magnesium sulphate, carbon dioxide and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q26a>MgCO<sub>3</sub>+ <input style="font-size: 16px; text-align: center;" size=1 name=q26b>H<sub>2</sub>SO<sub>4</sub> → <input style="font-size: 16px; text-align: center" size=1 name=q26c>MgSO<sub>4</sub>+ <input style="font-size: 16px; text-align: center;" size=1 name=q26d>CO<sub>2</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q26e>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(26,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,1,0,'MgCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','MgSO<sub>4</sub>+ CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(26,'Reactions of Sulphuric acid (As an acid)',1,1,1,1,1,0,'MgCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','MgSO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
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23.Zinc carbonate reacts with dilute Sulphuric acid to form Zinc sulphate, carbon dioxide and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q27a>ZnCO<sub>3</sub>+ <input style="font-size: 16px; text-align: center;" size=1 name=q27b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center" size=1 name=q27c>ZnSO<sub>4</sub>+ <input style="font-size: 16px; text-align: center;" size=1 name=q27d>CO<sub>2</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q27e>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(27,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,1,0,'ZnCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','ZnSO<sub>4</sub>+ CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(27,'Reactions of Sulphuric acid (As an acid)',1,1,1,1,1,0,'ZnCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','ZnSO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
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24.Copper (II) carbonate reacts with dilute Sulphuric acid to form Copper (II) sulphate, carbon dioxide and water:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q28a>CuCO<sub>3</sub>+ <input style="font-size: 16px; text-align: center;" size=1 name=q28b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q28c>CuSO<sub>4</sub>+ <input style="font-size: 16px; text-align: center;" size=1 name=q28d>CO<sub>2</sub>+<input style="font-size: 16px; text-align: center;" size=1 name=q28e>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(28,'Reactions of Sulphuric Acid (As an acid)',1,1,1,1,1,0,'CuCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','CuSO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(28,'Reactions of Sulphuric acid (As an acid)',1,1,1,1,1,0,'CuCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','CuSO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Show answer"></p>
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<h4>Reactions of concentrated Sulphuric Acid (As an oxidizing agent)</h4>
1. Hot concentrated Sulphuric acid oxidizes Copper metal into Copper(II)sulphate:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q29a>Cu + <input style="font-size: 16px; text-align: center;" size=1 name=q29b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center" size=1 name=q29c>CuSO<sub>4</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q29d>SO<sub>2</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q29e>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(29,'Reactions of Sulphuric Acid (As an oxidizing agent)',1,2,1,1,2,0,'Cu + H<sub>2</sub>SO<sub>4</sub>','CuSO<sub>4</sub> + SO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(29,'Reactions of Sulphuric acid (As an oxidizing agent)',1,2,1,1,2,0,'Cu + 2H<sub>2</sub>SO<sub>4</sub>','CuSO<sub>4</sub> + SO<sub>2</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
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2.Hot concentrated Sulphuric acid oxidizes Carbon into Carbon dioxide gas:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q30a>C + <input style="font-size: 16px; text-align: center;" size=1 name=q30b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q30c>CO<sub>2</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q30d>SO<sub>2</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q30e>H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(30,'Reactions of Sulphuric Acid (As an oxidizing agent)',1,2,1,2,2,0,'C + H<sub>2</sub>SO<sub>4</sub>','CO<sub>2</sub> + SO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(30,'Reactions of Sulphuric acid (As an oxidizing agent)',1,2,1,2,2,0,'C + 2H<sub>2</sub>SO<sub>4</sub>','CO<sub>2</sub> + 2SO<sub>2</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
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3.Hot concentrated Sulphuric acid oxidizes Sulphur into Sulphur dioxide:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q31a>S + <input style="font-size: 16px; text-align: center;" size=1 name=q31b>H<sub>2</sub>SO<sub>4</sub> →<input style="font-size: 16px; text-align: center;" size=1 name=q31c>SO<sub>2</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q31d>H<sub>2</sub>O </p>
<p style="font-size:115%; text-align:center;"><input onclick="check(31,'Reactions of Sulphuric Acid (As an oxidizing agent)',1,2,3,2,0,0,'S + H<sub>2</sub>SO<sub>4</sub>',' SO<sub>2</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(31,'Reactions of Sulphuric acid (As an oxidizing agent)',1,2,3,2,0,0,'S + 2H<sub>2</sub>SO<sub>4</sub>','3SO<sub>2</sub> + 2H<sub>2</sub>O');" type="button" value="Show answer"></p>
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<h4>Reactions of concentrated Sulphuric Acid (As a dehydrating agent)</h4>
1. Concentrated Sulphuric acid dehydrates sugar into Carbon:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q32a>C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> →<input style="font-size: 16px; text-align: center" size=1 name=q32b>C + <input style="font-size: 16px; text-align: center;" size=1 name=q32c> H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(32,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,12,11,0,0,0,'C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> + H<sub>2</sub>SO<sub>4</sub>','C + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(32,'Reactions of Sulphuric acid (As a dehydrating agent)',1,12,11,0,0,0,'C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> ','12C + 11H<sub>2</sub>O');" type="button" value="Show answer"></p>
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2. Concentrated Sulphuric acid dehydrates blue crystals of hydrated copper (II) sulphate into white anhydrous copper (II) sulphate powder:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q33a>CuSO<sub>4</sub>.5H<sub>2</sub>O →<input style="font-size: 16px; text-align: center;" size=1 name=q33b>CuSO<sub>4</sub> <input style="font-size: 16px; text-align: center;" size=1 name=q33c> H<sub>2</sub>O</p>
<p style="font-size:115%; text-align:center;"><input onclick="check(33,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,5,0,0,0,'CuSO<sub>4</sub>.5H<sub>2</sub>O','CuSO<sub>4</sub> + H<sub>2</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(33,'Reactions of Sulphuric acid (As a dehydrating agent)',1,1,5,0,0,0,'CuSO<sub>4</sub>.5H<sub>2</sub>O','CuSO<sub>4</sub> + 5H<sub>2</sub>O');" type="button" value="Show answer"></p>
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<h4>Reactions of concentrated Sulphuric Acid (As a less volatile acid)</h4>
1. Concentrated Sulphuric acid reacts with Potassium chloride to form Hydrogen chloride gas and Potassium bisulphate:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q34a>KCl + <input style="font-size: 16px; text-align: center;" size=1 name=q34b>H<sub>2</sub>SO<sub>4</sub> → <input style="font-size: 16px; text-align: center" size=1 name=q34c> HCl+ <input style="font-size: 16px; text-align: center;" size=1 name=q34d>KHSO<sub>4</sub></p>
<p style="font-size:115%; text-align:center;"><input onclick="check(34,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,1,1,0,0,'KCl + H<sub>2</sub>SO<sub>4</sub>','HCl + KHSO<sub>4</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(34,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,1,1,0,0,'KCl + H<sub>2</sub>SO<sub>4</sub>','HCl + KHSO<sub>4</sub>');" type="button" value="Show answer"></p>
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2. Concentrated Sulphuric acid reacts with Sodium chloride to form Hydrogen chloride gas and Sodium bisulphate:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q35a>NaCl + <input style="font-size: 16px; text-align: center;" size=1 name=q35b>H<sub>2</sub>SO<sub>4</sub> → <input style="font-size: 16px; text-align: center" size=1 name=q35c> HCl+ <input style="font-size: 16px; text-align: center;" size=1 name=q35d>NaHSO<sub>4</sub></p>
<p style="font-size:115%; text-align:center;"><input onclick="check(35,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,1,1,0,0,'NaCl + H<sub>2</sub>SO<sub>4</sub>','HCl + NaHSO<sub>4</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(35,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,1,1,0,0,'NaCl + H<sub>2</sub>SO<sub>4</sub>','HCl + NaHSO<sub>4</sub>');" type="button" value="Show answer"></p>
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3. Concentrated Sulphuric acid reacts with Potassium nitrate to form Nitric acid and Potassium bisulphate:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q36a>KNO<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q36b>H<sub>2</sub>SO<sub>4</sub> → <input style="font-size: 16px; text-align: center" size=1 name=q36c> HNO<sub>3</sub> <input style="font-size: 16px; text-align: center;" size=1 name=q36d>KHSO<sub>4</sub></p>
<p style="font-size:115%; text-align:center;"><input onclick="check(36,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,1,1,0,0,'KNO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','HNO<sub>3</sub> + KHSO<sub>4</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(36,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,1,1,0,0,'KNO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','HNO<sub>3</sub> + KHSO<sub>4</sub>');" type="button" value="Show answer"></p>
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4. Concentrated Sulphuric acid reacts with Sodium nitrate to form Nitric acid and Sodium bisulphate:
<p style="font-size:115%; text-align:center;"><input style="font-size: 16px; text-align: center;" size=1 name=q37a>NaNO<sub>3</sub> + <input style="font-size: 16px; text-align: center;" size=1 name=q37b>H<sub>2</sub>SO<sub>4</sub> → <input style="font-size: 16px; text-align: center" size=1 name=q37c> HNO<sub>3</sub>+ <input style="font-size: 16px; text-align: center;" size=1 name=q37d>NaHSO<sub>4</sub></p>
<p style="font-size:115%; text-align:center;"><input onclick="check(37,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,1,1,0,0,'NaNO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','HNO<sub>3</sub> + NaHSO<sub>4</sub>O');" type="button" value="Check answer"> <input type="reset" value="Reset"> <input onclick="show(37,'Reactions of Sulphuric Acid (As a dehydrating agent)',1,1,1,1,0,0,'NaNO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub>','HNO<sub>3</sub> + NaHSO<sub>4</sub>');" type="button" value="Show answer"></p>
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