main_day2_lab2.ipynb

{
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   "cell_type": "markdown",
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   "source": [
    "# List Comprehensions\n",
    "\n",
    "Complete the following set of exercises to solidify your knowledge of list comprehensions."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [],
   "source": [
    "import os"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "#### 1. Use a list comprehension to create and print a list of consecutive integers starting with 1 and ending with 50."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50]\n"
     ]
    }
   ],
   "source": [
    "lista_numeros=[x for x in range(1,51)]\n",
    "print(lista_numeros)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "#### 2. Use a list comprehension to create and print a list of even numbers starting with 2 and ending with 200."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 11,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100, 102, 104, 106, 108, 110, 112, 114, 116, 118, 120, 122, 124, 126, 128, 130, 132, 134, 136, 138, 140, 142, 144, 146, 148, 150, 152, 154, 156, 158, 160, 162, 164, 166, 168, 170, 172, 174, 176, 178, 180, 182, 184, 186, 188, 190, 192, 194, 196, 198, 200]\n"
     ]
    }
   ],
   "source": [
    "lista_numeros_2=[x for x in range(2,201) if x%2==0 ]\n",
    "print (lista_numeros_2)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "#### 3. Use a list comprehension to create and print a list containing all elements of the 10 x 4 array below."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 13,
   "metadata": {},
   "outputs": [],
   "source": [
    "a = [[0.84062117, 0.48006452, 0.7876326 , 0.77109654],\n",
    "       [0.44409793, 0.09014516, 0.81835917, 0.87645456],\n",
    "       [0.7066597 , 0.09610873, 0.41247947, 0.57433389],\n",
    "       [0.29960807, 0.42315023, 0.34452557, 0.4751035 ],\n",
    "       [0.17003563, 0.46843998, 0.92796258, 0.69814654],\n",
    "       [0.41290051, 0.19561071, 0.16284783, 0.97016248],\n",
    "       [0.71725408, 0.87702738, 0.31244595, 0.76615487],\n",
    "       [0.20754036, 0.57871812, 0.07214068, 0.40356048],\n",
    "       [0.12149553, 0.53222417, 0.9976855 , 0.12536346],\n",
    "       [0.80930099, 0.50962849, 0.94555126, 0.33364763]];"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 27,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0.84062117, 0.48006452, 0.7876326, 0.77109654, 0.44409793, 0.09014516, 0.81835917, 0.87645456, 0.7066597, 0.09610873, 0.41247947, 0.57433389, 0.29960807, 0.42315023, 0.34452557, 0.4751035, 0.17003563, 0.46843998, 0.92796258, 0.69814654, 0.41290051, 0.19561071, 0.16284783, 0.97016248, 0.71725408, 0.87702738, 0.31244595, 0.76615487, 0.20754036, 0.57871812, 0.07214068, 0.40356048, 0.12149553, 0.53222417, 0.9976855, 0.12536346, 0.80930099, 0.50962849, 0.94555126, 0.33364763]\n"
     ]
    }
   ],
   "source": [
    "list3=[valor for element in a for valor in element]\n",
    "print(list3)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "#### 4. Add a condition to the list comprehension above so that only values greater than or equal to 0.5 are printed."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 29,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0.84062117, 0.7876326, 0.77109654, 0.81835917, 0.87645456, 0.7066597, 0.57433389, 0.92796258, 0.69814654, 0.97016248, 0.71725408, 0.87702738, 0.76615487, 0.57871812, 0.53222417, 0.9976855, 0.80930099, 0.50962849, 0.94555126]\n"
     ]
    }
   ],
   "source": [
    "list3=[valor for element in a for valor in element if valor>=.5]\n",
    "print(list3)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "#### 5. Use a list comprehension to create and print a list containing all elements of the 5 x 2 x 3 array below."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 31,
   "metadata": {},
   "outputs": [],
   "source": [
    "b = [[[0.55867166, 0.06210792, 0.08147297],\n",
    "        [0.82579068, 0.91512478, 0.06833034]],\n",
    "\n",
    "       [[0.05440634, 0.65857693, 0.30296619],\n",
    "        [0.06769833, 0.96031863, 0.51293743]],\n",
    "\n",
    "       [[0.09143215, 0.71893382, 0.45850679],\n",
    "        [0.58256464, 0.59005654, 0.56266457]],\n",
    "\n",
    "       [[0.71600294, 0.87392666, 0.11434044],\n",
    "        [0.8694668 , 0.65669313, 0.10708681]],\n",
    "\n",
    "       [[0.07529684, 0.46470767, 0.47984544],\n",
    "        [0.65368638, 0.14901286, 0.23760688]]];"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 35,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0.55867166, 0.06210792, 0.08147297, 0.82579068, 0.91512478, 0.06833034, 0.05440634, 0.65857693, 0.30296619, 0.06769833, 0.96031863, 0.51293743, 0.09143215, 0.71893382, 0.45850679, 0.58256464, 0.59005654, 0.56266457, 0.71600294, 0.87392666, 0.11434044, 0.8694668, 0.65669313, 0.10708681, 0.07529684, 0.46470767, 0.47984544, 0.65368638, 0.14901286, 0.23760688]\n"
     ]
    }
   ],
   "source": [
    "list4=[g for element in b for value in element for g in value]\n",
    "print (list4)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "#### 6. Add a condition to the list comprehension above so that the last value in each subarray is printed, but only if it is less than or equal to 0.5."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 53,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[[0.55867166, 0.06210792, 0.08147297], [0.82579068, 0.91512478, 0.06833034], [0.05440634, 0.65857693, 0.30296619], [0.09143215, 0.71893382, 0.45850679], [0.71600294, 0.87392666, 0.11434044], [0.8694668, 0.65669313, 0.10708681], [0.07529684, 0.46470767, 0.47984544], [0.65368638, 0.14901286, 0.23760688]]\n"
     ]
    }
   ],
   "source": [
    "list4=[value for element in b for value in element if value[-1]<=.5]\n",
    "print (list4)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Bonus"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Try to solve these katas using list comprehensions."
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**Easy**\n",
    "- [Insert values](https://www.codewars.com/kata/invert-values)\n",
    "- [Sum Square(n)](https://www.codewars.com/kata/square-n-sum)\n",
    "- [Digitize](https://www.codewars.com/kata/digitize)\n",
    "- [List filtering](https://www.codewars.com/kata/list-filtering)\n",
    "- [Arithmetic list](https://www.codewars.com/kata/541da001259d9ca85d000688)\n",
    "\n",
    "**Medium**\n",
    "- [Multiples of 3 or 5](https://www.codewars.com/kata/514b92a657cdc65150000006)\n",
    "- [Count of positives / sum of negatives](https://www.codewars.com/kata/count-of-positives-slash-sum-of-negatives)\n",
    "- [Categorize new member](https://www.codewars.com/kata/5502c9e7b3216ec63c0001aa)\n",
    "\n",
    "**Advanced**\n",
    "- [Queue time counter](https://www.codewars.com/kata/queue-time-counter)"
   ]
  }
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