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We are aware of the method, and it is pretty cool indeed. However, most people are not willing to take their machine apart to test the inertia of the flywheel. For most commercial machines, people choose to adjust the inertia experimentally to match their expected power/speed. |
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The physics link has a link with D.Vernooy doc https://dvernooy.github.io/projects/ergware/
With Dave I tested another way to find Flywheel Inertia, I tested my flywheel in both way and the result is quite the same, but this solution is more simple (in my opinion).
The formula derived from the "parallel axis theorem". (provided me from Dave Vernooy)
My test
using my stopwatch I get 5.28 seconds for 2 swings back and forth. So this means T = 5.28/2 = 2.64 seconds. With M = 1.91 kg and L = 1.71M, here is what I calculate from my formula:
I = 0.249 * M * L* T^2 - M * L^2
= 0.2491.911.712.64^2 - 1.911.71^2
= 0.2491.911.712.642.64 - 1.911.711.71
= 5.66808 - 5.585031
= 0.083 kg*m^2
So I = 0.08 kg*m^2 for flywheel. Very similar to spreadsheet.
video_2023-01-13_08-55-32.mp4
I hope it can be useful for someone
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