README_EN.md

1178. Number of Valid Words for Each Puzzle

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Description

With respect to a given puzzle string, a word is valid if both the following conditions are satisfied:

• word contains the first letter of puzzle.
• For each letter in word, that letter is in puzzle.
  • For example, if the puzzle is "abcdefg", then valid words are "faced", "cabbage", and "baggage", while
  • invalid words are "beefed" (does not include 'a') and "based" (includes 's' which is not in the puzzle).

Return an array answer, where answer[i] is the number of words in the given word list words that is valid with respect to the puzzle puzzles[i].

 

Example 1:

Input: words = ["aaaa","asas","able","ability","actt","actor","access"], puzzles = ["aboveyz","abrodyz","abslute","absoryz","actresz","gaswxyz"]
Output: [1,1,3,2,4,0]
Explanation: 
1 valid word for "aboveyz" : "aaaa" 
1 valid word for "abrodyz" : "aaaa"
3 valid words for "abslute" : "aaaa", "asas", "able"
2 valid words for "absoryz" : "aaaa", "asas"
4 valid words for "actresz" : "aaaa", "asas", "actt", "access"
There are no valid words for "gaswxyz" cause none of the words in the list contains letter 'g'.

Example 2:

Input: words = ["apple","pleas","please"], puzzles = ["aelwxyz","aelpxyz","aelpsxy","saelpxy","xaelpsy"]
Output: [0,1,3,2,0]

 

Constraints:

• 1 <= words.length <= 105
• 4 <= words[i].length <= 50
• 1 <= puzzles.length <= 104
• puzzles[i].length == 7
• words[i] and puzzles[i] consist of lowercase English letters.
• Each puzzles[i] does not contain repeated characters.

Solutions

Python3

class Solution:
    def findNumOfValidWords(self, words: List[str], puzzles: List[str]) -> List[int]:
        cnt = Counter()
        for w in words:
            mask = 0
            for c in w:
                mask |= 1 << (ord(c) - ord("a"))
            cnt[mask] += 1

        ans = []
        for p in puzzles:
            mask = 0
            for c in p:
                mask |= 1 << (ord(c) - ord("a"))
            x, i, j = 0, ord(p[0]) - ord("a"), mask
            while j:
                if j >> i & 1:
                    x += cnt[j]
                j = (j - 1) & mask
            ans.append(x)
        return ans

Java

class Solution {
    public List<Integer> findNumOfValidWords(String[] words, String[] puzzles) {
        Map<Integer, Integer> cnt = new HashMap<>(words.length);
        for (var w : words) {
            int mask = 0;
            for (int i = 0; i < w.length(); ++i) {
                mask |= 1 << (w.charAt(i) - 'a');
            }
            cnt.merge(mask, 1, Integer::sum);
        }
        List<Integer> ans = new ArrayList<>();
        for (var p : puzzles) {
            int mask = 0;
            for (int i = 0; i < p.length(); ++i) {
                mask |= 1 << (p.charAt(i) - 'a');
            }
            int x = 0;
            int i = p.charAt(0) - 'a';
            for (int j = mask; j > 0; j = (j - 1) & mask) {
                if ((j >> i & 1) == 1) {
                    x += cnt.getOrDefault(j, 0);
                }
            }
            ans.add(x);
        }
        return ans;
    }
}

C++

class Solution {
public:
    vector<int> findNumOfValidWords(vector<string>& words, vector<string>& puzzles) {
        unordered_map<int, int> cnt;
        for (auto& w : words) {
            int mask = 0;
            for (char& c : w) {
                mask |= 1 << (c - 'a');
            }
            cnt[mask]++;
        }
        vector<int> ans;
        for (auto& p : puzzles) {
            int mask = 0;
            for (char& c : p) {
                mask |= 1 << (c - 'a');
            }
            int x = 0;
            int i = p[0] - 'a';
            for (int j = mask; j; j = (j - 1) & mask) {
                if (j >> i & 1) {
                    x += cnt[j];
                }
            }
            ans.push_back(x);
        }
        return ans;
    }
};

Go

func findNumOfValidWords(words []string, puzzles []string) (ans []int) {
	cnt := map[int]int{}
	for _, w := range words {
		mask := 0
		for _, c := range w {
			mask |= 1 << (c - 'a')
		}
		cnt[mask]++
	}
	for _, p := range puzzles {
		mask := 0
		for _, c := range p {
			mask |= 1 << (c - 'a')
		}
		x, i := 0, p[0]-'a'
		for j := mask; j > 0; j = (j - 1) & mask {
			if j>>i&1 > 0 {
				x += cnt[j]
			}
		}
		ans = append(ans, x)
	}
	return
}

TypeScript

function findNumOfValidWords(words: string[], puzzles: string[]): number[] {
    const cnt: Map<number, number> = new Map();
    for (const w of words) {
        let mask = 0;
        for (const c of w) {
            mask |= 1 << (c.charCodeAt(0) - 97);
        }
        cnt.set(mask, (cnt.get(mask) || 0) + 1);
    }
    const ans: number[] = [];
    for (const p of puzzles) {
        let mask = 0;
        for (const c of p) {
            mask |= 1 << (c.charCodeAt(0) - 97);
        }
        let x = 0;
        const i = p.charCodeAt(0) - 97;
        for (let j = mask; j; j = (j - 1) & mask) {
            if ((j >> i) & 1) {
                x += cnt.get(j) || 0;
            }
        }
        ans.push(x);
    }
    return ans;
}

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