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lc912.java
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package code;
/*
* 912. Sort an Array
* 题意:数组排序
* 难度:Medium
* 分类:
* 思路:
* Tips:注意和lc215区别
* lc215
*/
public class lc912 {
public static void main(String[] args) {
int[] arr = sortArray3(new int[]{5,2,3,1});
for(int i: arr){
System.out.println(i);
}
}
// 快排
public int[] sortArray(int[] nums) {
quickSort(nums, 0, nums.length-1);
return nums;
}
public void quickSort(int[] nums, int left, int right){
if(left>=right) return; //注意返回
int l = left;
int r = right;
int pivot = nums[left];
while(left<right){
while(left<right && nums[right]>=pivot) right--;
int temp = nums[right]; nums[right] = nums[left]; nums[left]=temp; //交换
while(left<right && nums[left]<pivot ) left++;
temp = nums[right]; nums[right] = nums[left]; nums[left]=temp;
}
nums[left] = pivot;
quickSort(nums, left+1, r);
quickSort(nums, l, right-1);
}
// 归并
public static int[] sortArray2(int[] nums) {
mergeSort(nums, 0, nums.length-1);
return nums;
}
public static void mergeSort(int[] nums, int left, int right){
if(left<right) {
int mid = (left+right)/2;
mergeSort(nums, left, mid);
mergeSort(nums, mid+1, right);
merge(nums, left, mid, right);
}
}
public static void merge(int[] nums, int left, int mid, int right){
int[] temp = nums.clone(); //记住这个方法
int cur = left;
int pos1 = left;
int pos2 = mid+1;
while(pos1<=mid && pos2<=right){
if(temp[pos1]<temp[pos2]) { //注意是temp 复制后的
nums[cur] = temp[pos1];
pos1++;
cur++;
}
else {
nums[cur] = temp[pos2];
pos2++;
cur++;
}
}
while(pos1<=mid){
nums[cur] = temp[pos1];
pos1++;
cur++;
}
while(pos2<=right){
nums[cur] = temp[pos2];
pos2++;
cur++;
}
}
//堆排
public static int[] sortArray3(int[] nums) {
//建堆
int pos = nums.length/2;
while(pos>=0){
AdjustTree(nums, nums.length-1, pos);
pos--;
}
//排序,每次找出最大的,从堆中去掉,调整堆
int cur = nums.length-1;
while(cur>=0){
//交换位置
int temp = nums[0];
nums[0] = nums[cur];
nums[cur] = temp;
cur--;
AdjustTree(nums, cur, 0);
}
return nums;
}
public static void AdjustTree(int[] nums, int len, int pos){ //调整堆
int pos_exchange = pos*2+1;
while(pos_exchange<=len){ //left
if(pos_exchange+1<=len&&nums[pos_exchange+1]>nums[pos_exchange]){ //比较左右节点,挑出来大的
pos_exchange += 1;
}
if(nums[pos_exchange]>nums[pos]){ //和父节点比较
int temp = nums[pos];
nums[pos] = nums[pos_exchange];
nums[pos_exchange] = temp;
pos = pos_exchange;
pos_exchange = pos*2+1;
}else{
break;
}
}
}
}