Brute Force
/**
* Question : 1. 2Sum
* Complexity : Time: O(n^2) ; Space: O(1)
* Topics : array
*/
class Solution {
public int[] twoSum(int[] nums, int target) {
for (int i = 0; i < nums.length; i++) {
for (int j = i + 1; j < nums.length; j++) {
if (nums[i] + nums[j] == target) {
return new int[]{i, j};
}
}
}
return new int[]{};
}
}
Hash Table
/**
* Question : 1. 2Sum
* Complexity : Time: O(n) ; Space: O(n)
* Topics : array
*/
class Solution {
public int[] twoSum(int[] arr, int target) {
HashMap<Integer, Integer> map = new HashMap<>();
for (int i = 0; i < arr.length; i++) {
int want = target - arr[i];
if (map.containsKey(want)) {
return new int[]{map.get(want), i};
}
map.put(arr[i], i);
}
return new int[]{};
}
}