DP
/**
* Question : 646. Maximum Length of Pair Chain
* Complexity : Time: O(n^2) ; Space: O(n)
* Topics : DP
*/
public class Solution {
public int findLongestChain(int[][] pairs) {
Arrays.sort(pairs, (a, b) -> {
if (a != b) {
return a[0] - b[0];
}
return a[1] - b[1];
});
int n = pairs.length;
// dp[i] = longest pair chain for index i.
int[] dp = new int[n];
Arrays.fill(dp, 1);
for (int i = 1; i < n; i++) {
for (int j = 0; j < i; j++) {
int[] a = pairs[i];
int[] b = pairs[j];
if (b[1] < a[0]) {
dp[i] = Math.max(dp[i], dp[j] + 1);
}
}
}
return dp[n - 1];
}
}