-
Notifications
You must be signed in to change notification settings - Fork 183
/
24 - Day 23 - BST Level-Order Traversal.py
57 lines (49 loc) · 1.43 KB
/
24 - Day 23 - BST Level-Order Traversal.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
# ========================
# Information
# ========================
# Direct Link: https://www.hackerrank.com/challenges/30-binary-trees/problem
# Difficulty: Easy
# Max Score: 30
# Language: Python
# ========================
# Solution
# ========================
import sys
class Node:
def __init__(self, data):
self.right = self.left = None
self.data = data
class Solution:
def insert(self, root, data):
if root == None:
return Node(data)
else:
if data <= root.data:
cur = self.insert(root.left, data)
root.left = cur
else:
cur = self.insert(root.right, data)
root.right = cur
return root
def levelOrder(self, root):
# Write your code here
nodes_queue = []
data_list = []
temp_node = root
while temp_node:
data_list.append(temp_node.data)
if temp_node.left is not None:
nodes_queue.append(temp_node.left)
if temp_node.right is not None:
nodes_queue.append(temp_node.right)
if len(nodes_queue) == 0:
break
temp_node = nodes_queue.pop(0)
print(' '.join(list(map(str, data_list))))
T = int(input())
myTree = Solution()
root = None
for i in range(T):
data = int(input())
root = myTree.insert(root, data)
myTree.levelOrder(root)